Same thing as what you did on the bottom. Find numbers with both 7 as the base and numbers that add to 14 on the top. Possibilities:
1) 7^10•7^4
2)7^6•7^8
37^2•7^12
<em>Answer : C: $125.</em>
Hopefully that helps you ! have a good day !
Answer: The set does not have a solution
Step-by-step explanation:
Adding Equations 1 & 3 we get 5x = 7. This gives x = 7/5
Putting this value of x in eq. 2 we get
-2y + 2z = -1-(7/5) or
2y - 2z = 12/5 or 5y - 5z = 6
Multiplying eq. 1 by 2 we get
4x + 2y - 2z = 6
adding this with eq. 2 we get 5x = 5 or x = 1
As the common solution for x from equations 1&3 does not satisfy eq. 1&2 it comes out that the three equations do not have a common solution.
Same can be verified by using different sets of two equations also.
Answer:
It is 5. I got it right on khan academy! Thanks for the answer!
Step-by-step explanation:
