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3 years ago

Math Help plases I need an answer

Mathematics

1 answer:

Makovka662 [10]3 years ago

5 0

The answer would be A, since the median is 14 and that is where the middle line is at

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Andrea has 18 yards of fabric. How many 4-inch pieces can she cut from her original piece?

Mrac [35]

Answer:

162 pieces

Step-by-step explanation:

Andrea has 18 yards

How many 4 inch pieces can she get?

Convert

1 yard = 3 feet

18 yards = 54 feet

1 foot = 12 inches

54 feet = 648 inches

Divide

648 inches ÷ 4 inches = 162 pieces

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Help me on this I really need it

CaHeK987 [17]

Answer:

Step-by-step explanation:

Given that sale of grills increase 6% per year

CUrrent sale of grills this year = 3300

So in the first year sales would increase by 3300(6%)

Total sales in the I year =3300+3300(6%)

This will be again increasing by 6% in II year and so on.

Hence we have

every year 3300 increases by 6% compoundly

No of sales in t year

= $3300(1+0.06)^t\\=3300(1.06^t)$

In 6th year sale

s(6) = $3300(1.06)^6\\=4681.11$

7 0

3 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

1 year ago

a guy is washing 32 feet off the ground. he positions the ladder at an angle of 67° with the ground. how tall is the ladder

irina [24]

Answer:

34.76 feet

Step-by-step explanation:

trig

SOH CAH TOA