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3 years ago

Math Help plases I need an answer

Mathematics

1 answer:

Makovka662 [10]3 years ago

5 0

The answer would be A, since the median is 14 and that is where the middle line is at

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The crafting club sold art calendars for a recent fundraiser. The table below lists the number of calendars sold by each member

solniwko [45]

Answer:

there is no table below, you have to add a picture

Step-by-step explanation:

3 0

3 years ago

2. a) How many milliseconds (ms) are in 1 second? 1. b) How many microseconds (μs) are in 1 second? 2. c) How many nanoseconds (

olchik [2.2K]

Answer and explanation:

a) How many milliseconds (ms) are in 1 second?

1 second = 1000 milliseconds

1 second = $10^3$ milliseconds

b) How many microseconds (μs) are in 1 second?

1 second = 1000000 microseconds

1 second = $10^6$ microseconds

c) How many nanoseconds (ns) are in 1 millisecond?

1 millisecond = 1000000 nanoseconds

1 millisecond = $10^6$ nanoseconds

d) How many microseconds are in 1 millisecond?

1 millisecond = 1000 microseconds

1 millisecond = $10^3$ microseconds

e) How many nanoseconds are in 1 microsecond?

1 microsecond = 1000 nanoseconds

1 microsecond = $10^3$ nanoseconds

f) How many kilobytes (KB) are in 1 gigabyte (GB)?

1 gigabyte = 1000000 kilobytes

1 gigabyte = $10^6$ kilobytes

g) How many kilobytes are in 1 megabyte (MB)?

1 megabyte = 1000 kilobytes

1 megabyte = $10^3$ kilobytes

h) How many megabytes are in 1 gigabyte?

1 gigabyte = 1000 megabytes

1 gigabyte = $10^3$ megabytes

i) How many bytes are in 20 megabytes?

1 megabytes = 1000000 bytes

20 megabytes = 20000000 bytes

20 megabytes = $2\times 10^7$ bytes

j) How many kilobytes are in 2 gigabytes?

1 megabyte = 1000 kilobytes

2 megabyte = 2000 kilobytes

2 megabyte = $2\times 10^3$ kilobytes

4 0

3 years ago

Each team in the softball league plays each of the other teams exactly once. If

Aleks04 [339]

<span>Each team in the softball league plays each of the other teams exactly once. For every game, there is 2 team playing. The order is not important because A vs B is same as B vs A
So you just need to makes a combination of 2 that have a result of 21. If there is t number of teams, the number of matches would be:
tC2 = t!/2!(t-2)! = 21
</span>t! / (t-2)! = 21 *2
(t)(t-1)= 42
t^2 -t -42=0
(t-7)(t+6)
t=7 ; t=-6

Excluding the minus result, you got 7 teams.

6 0

3 years ago

At time t=0 hours, a tank contains 3000 litres of water. Water leaks from the tank. At the end of every hour there is x% less wa

Margaret [11]

Answer:

x = 2; K = 0.98

Step-by-step explanation:

At time, t = 0, Volume of Water = 3,000 litres

After t hours , the Volume of water in the tank = Vt

At the end of every hour there is a x% less water in the tank then at the start of the hour

After 1 hour, volume of water left Vt = V1

V1 = 3,000 - 3000 × (x/100)

V1 = 3,000 - 30x

After 2 hours, Volume of water left is V2

V2 = (3,000 - 30 x) - (3,000 - 30 x) × (x/100)

V2 = (3,000 - 30 x) - (3000x - 30x²)/100

V2 = {100(3000 - 30x) - x(3000 - 30x)} /100

V2 = {(3000 - 30x)(100 - x)}/100

Recall, V2 = 2881.2

Therefore

{(3000 - 30x)(100 - x)}/100 = 2881.2

(3000 - 30x)(100 - x) = 288120

300000 - 3000 x - 3000 x + 30 x² = 288120

30 x ² - 6000 x + 11880 = 0

Dividing both sides by 30

x² - 200 x + 396=0

Factorizing:

(x -198)(x-2) = 0

x = 198 or x = 2

Since the percentage by which the water reduces cannot be greater than 100, x = 2 is chosen.

Step 2: Solving for k

Given that Vt=KtV0

K = Vt/V0

At t = 1

V1 = 3000 - 30x

V1 = 3000 - 30 × 2

V1 = 3000 - 60

V1 = 2940

K = 2940/3000

K = 0.98

5 0

3 years ago

Find 55% of 164 I don't get it I need help can someone help me like right now please

IgorC [24]

$55\%\ of\ 164\ is...\\\\ \frac{55}{100} \times \frac{164}{1} =\\\\55*164=9020\\100*1=100\\\\ \frac{9020}{100}\approx90\\\\20\ is\ left\ over.\\\\90.20\\\\\\55\%\ of\ 164\ is\ 90.2$

7 0

3 years ago