If you’re using the inspection method, what constant term would you need in the numerator of this rational expression for (x+5)
1 answer:
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(1, 3.5 ) and (3, 3.5 )
the endpoints of the midsegment are at the midpoints of DE and DF
using the midpoint formula with D(0, 7), E(2, 0), F(6, 0)
midpoint of DE = [(0 + 2),
(7 + 0)] = (1, 3.5)
midpoint of DF = [(0 + 6),
(7 + 0)] = (3, 3.5)