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steposvetlana [31]
3 years ago
11

Which of the following is a rational number

Mathematics
1 answer:
krek1111 [17]3 years ago
7 0
The answer is B because a rational number is a number that can be expressed as a fraction and 1.425 can be written as 1425/1000
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The local florist never has more than a combined total of 40 daisy and carnation bouquets and never more than 12 carnation bouqu
Marrrta [24]

The system of inequalities that represents this situation are

x + y ≤ 40 and x ≤ 12.

Here, x = Number of carnation bouquets

y = Number of daisy bouquets

From the system of inequalities,

In the first case.

The local florist has never more than a combined total of 40 daisy  bouquets, so according to this statement the following equation will be:

x + y ≤ 40.

Again in the second case.

The local florist has never more than a 12 carnation bouquets, so according to this statement the following equation will be:

x ≤ 12.

Therefore, the system of inequalities that represents this situation are

x + y ≤ 40 and x ≤ 12.

Learn more about system of inequalities here -

https://brainly.ph/question/9662691

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8 0
1 year ago
ayer/ Adding and Subtracting Radicals Pre-Test Active 1 2 3 4 5 7 8 9 10 TIME REMAINING 52:33 The formula S= SA 6 gives the leng
sammy [17]

Answer:

27

Step-by-step explanation:

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4 0
2 years ago
Round each number to the nearest ten. What is the best estimate for the answer to 343.42 – 39.87?
Nikolay [14]
So I would round it to 340 and 40 because if the number is lower than 5 than take it DOWN to the nearest ten if it's five or above take UP to the nearest ten

Hope it helped you
7 0
3 years ago
Can someone SMART actually help me
lisov135 [29]
The answer is 196/3 pi in^3. All you have to do is multiply 7x7, then you have to multiply that by 1/3 and 4, and you get 65.333333333. Then, you have to turn it into a fraction. You have to multiply 65 by 3, then add one, and you get 196/3 pi in^3.
7 0
3 years ago
What does y is two less than x stand for
solong [7]

Answer:

Y = X - 2 would be the answer.

5 0
3 years ago
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