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Kisachek [45]
3 years ago
11

What is the sum of the geometric sequence-1,6,36 if there are 6 terms

Mathematics
1 answer:
Reptile [31]3 years ago
5 0

Answer:

The sum is 9,331

Step-by-step explanation:

we have

1,6,36,...

we have

a1=1

a2=6

a3=36

Find the common ratio r

a2/a1=6/1=6

a3/a2=36/6=6

The common ratio is r=6

The formula to calculate the sum in a geometric sequence is equal to

S=a1\frac{(1-r^{n})}{(1-r)}

where

n is the number of terms

r is the common ratio

a1 is the first term

we have

n=6

a1=1

r=6

substitute

S=(1)\frac{(1-(6)^{6})}{(1-6)}

S=\frac{(1-(6)^{6})}{(-5)}

S=9,331

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A group of winning ticket holders share equally 90,000,000 lottery. Before the money is divided, three more winning ticket holde
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Let's assume

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Step-by-step explanation:

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