The equation, in slope-intercept form, of the line that is perpendicular to the line y- 4 = -(x-6) and passes through the point (-2,-2) is y = x.
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<h3>How to represent equation in slope intercept form?</h3>
The equation in slope intercept form is represented as follows;
y = mx + b
where
Therefore,
perpendicular lines follows the rule as follows;
m₁m₂ = -1
Therefore,
y - 4 = -(x - 6)
y - 4 = -x + 6
y = -x + 6 + 4
y = -x + 10
Therefore,
-1m₂ = -1
m₂ = 1
Hence, the line passes through (-2, -2).
Therefore,
-2 = 1(-2) + b
b = -2 + 2
b = 0
Therefore, the equation is as follows;
y = x
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A looks like the correct answer
Answer:
see explanation
Step-by-step explanation:
A
The area (A) of a circle is calculated as
A = πr² ( r is the radius )
Here diameter = 12 , then radius = 12 ÷ 2 = 6 , then
A = π × 6² = 3.14 × 36 = 113.04 m²
B
The circumference (C) of a circle is calculated as
C = 2πr ( r is the radius )
Here C = 28.26 , then
2πr = 28.26 ( divide both sides by 2π )
r = 
= 
= 4.5 in
Answer:
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Just divide 5/4 = 1.25. Thank you.
