<h2>25 </h2>
Step-by-step explanation:
<h3><em>=</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>(</em><em>5</em><em> </em><em>-</em><em> </em><em>1</em><em>)</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>3</em><em> </em><em>×</em><em> </em><em>4</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>1</em><em>2</em><em> </em><em>+</em><em> </em><em>1</em><em>3</em></h3><h3><em>=</em><em> </em><em>2</em><em>5</em></h3>
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Add all the minutes together, then divide by the number of students:
21+35+77+48+24+29+37+98+30+7 = 406 total minutes
10 students.
Average = 406 / 10 = 40.6 minutes per week.
The answer is A.
<span>2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
</span><span>x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
</span><span>x = -(3 / 4) + sq root (-36) / 4
</span><span>x = -(3 / 4) - sq root (-36) / 4
</span>
Answer:
25.5 mph
Step-by-step explanation:
So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed
So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15
y=2(0.25)+40
y=0.5+40
y=40.5
So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed
40.5 - 15 = 25.5
Answer:
$5.79 +
$0.95
Estamate
$5.80 +
$1.00
= $6.80
We only round one digit.
Step-by-step explanation:
