First you need to set up an equation y = mx + b. m would be the monthly charge and b would be the one time fee. x represents the number of months.
To solve for the number of months with a total price of 240 we substitute 240 in for y and solve for x.
240 = 25x + 40
subtract 40 from each side
200= 25x
divide by 25
8 = x
8 months
10 + 7r = 45
7r = 35
r = 5
5 miles
B and C are both correct
t(s) is equivalent to the temperature of the tea after s amount of seconds
Answer:
8+2
Step-by-step explanation:
2+2+2+2+
+
=8+2
4^2+2^2=h^2
20=h^2
h=
Step-by-step explanation:
SAS is Side - Angle (between the sides) - Side
BC and CD are shown to be congruent with the markers that cross the line segments.
AC and AC are the same because they are the same.
The only things needed are the congruent angles between the sides.
The angles are ACD and ACB, because those are the angles between AC and BC and AC and CD.
Answer:
The answer is "".
Step-by-step explanation:
Please find the complete question in the attached file.
We select a sample size n from the confidence interval with the mean
and default
, then the mean take seriously given as the straight line with a z score given by the confidence interval

Using formula:
The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution
the required probability:
