Question

Line segment AB has a length of 4 units. It is translated 2 units to the right on a coordinate plane to obtain line segment A'B'. What is the length of A'B'?

Answer 1

Answer: The length of A'B' is 4 units.

Step-by-step explanation:  Given that the line segment AB has a length of 4 units and it is translated 2 units to the right on a coordinate plane to obtain line segment A'B'.

We are to find the length of A'B'.

According to the given information, the line segment AB is translated 2 units to the right.

So, the point A and B, both will be translated two units to the right.

Let us consider the co-ordinates of the endpoints of AB are (1, 2) and (5, 2), so that the length of AB (using distance formula) is

$AB=\sqrt{(5-1)^2+(2-2)^2}=\sqrt{16}=4~\textup{units}.$

After translating 2 units right, the point A will translate to A'(3, 2) and B will translate to B'(7, 2).

Therefore, the length of A'B' will be

$A'B'=\sqrt{(7-3)^2+(2-2)^2}=\sqrt{16}=4~\textup{units}.$

Thus, the length of A'B' is 4 units.

Answer 2

length of the line segment does not change. you are just moving it 2 units to the right. answer would be 4 units