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3 years ago

11

Factor the polynomial -6x^3-12x^2-18x

2 answers:

laiz [17]3 years ago

7 0

Answer:

$\boxed{\bold{-6x\left(x^2+2x+3\right)}}$

Step By Step Explanation:

Apply Exponent Rule $\bold{a^{b+c}=a^ba^c}$

$\bold{x^2=xx}$

$\bold{x^3=x^2x}$

$\bold{-6x^2x-12xx-18x}$

Rewrite 18: $\bold{6\cdot \:3}$

Rewrite 12: $\bold{6\cdot \:2}$

$\bold{-6x^2x-6\cdot \:2xx-6\cdot \:3x}$

Factor Out Common Term $\bold{-6x}$

$\bold{-6x\left(x^2+2x+3\right)}$

$\boxed{\bold{Mordancy}}$

kati45 [8]3 years ago

4 0

Answer: -6x(x^2+2x+3)

Step-by-step explanation:

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If your going 16 mph and you drive 10m and a half how many hours did it take

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It took about 0.66 hour, which is basically 40 minutes.

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3 years ago

Read 2 more answers

What is the Ratio of 18:24, 4:70, 35:105, 22:7, 12:165, In fractions in their Simplest form?

Degger [83]

18:24 = 3/4
4:70 = 2/35
35:105 = 1/3
22:7 = 22/7
12:165 = 4/55

7 0

3 years ago

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

2 years ago

Select all the expression that have value of 25 a.500divided by 6 b. 600 divided by 3 c.100divided by 4 d.150 divided by 5 e.200

goldfiish [28.3K]

The answer is C. and E.
--
Work shown below:
A. 500 divided by 6 equals 83.33.
B. 600 divided by 3 equals 200.
C. 100 divided by 4 equals 25. (CORRECT)
D. 150 divided by 5 equals 30.
E. 200 divided by 8 equals 25. (CORRECT)
--
Hope this could help you.

7 0

3 years ago

the tens digit of a two digit number is twice the units digit. The sum of the digits is twelve. Find the original number.

KatRina [158]

X - tens digit
y - units digit

$x=2y\\
x+y=12\\\\
2y+y=12\\
3y=12\\
y=4\\\\
x=2\cdot4\\
x=8\\\\
10\cdot8+4=\boxed{84}
$

4 0

3 years ago