Answer: Edit: -0.0625
Step-by-step explanation:
Answer:
a) 
And if we solve for
we got:

b) False
The reason is because we don't satisfy the following relationship:

We have that:

c) False
In order to satisfy independence we need to have the following condition:

And for this case we don't satisfy this relation since:

Step-by-step explanation:
For this case we have the following probabilities given:

Part a
We want to calculate the following probability: 
And we can use the total probability rule given by:

And if we solve for
we got:

Part b
False
The reason is because we don't satisfy the following relationship:

We have that:

Part c
False
In order to satisfy independence we need to have the following condition:

And for this case we don't satisfy this relation since:

Answer: a burger is $5.25, fries are $1.50
b = burger, f = fries
3b + 3f = 20.25
5b + 8f = 38.25
First, solve for b in terms of f
3b = 20.25 - 3f
b = 6.75 -f
Then substitute that for b in the other equation to solve and get a numerical value for f.
5(6.75 -f) + 8f = 38.25
33.75 -5f +8f = 38.25
33.75 + 3f = 38.25
3f = 4.5
f = 1.5
Now substitute that in to get a numerical value for b
b = 6.75 - 1.5
b = 5.25
Checking the math:
3b + 3f = 20.25
3(5.25) + 3(1.5) = 15.75 + 4.5 = 20.25
Answer:
(1) 3.43
Step-by-step explanation:
tan θ = y / x
tan θ = 0.96 / 0.28
tan θ = 3.43