24x-45y=34x

To solve for y, subtract 24x:
-45y=10x

Divide by -45:
y=-10/45x

Reduce:
y=-2/9x

To solve for x, subtract 24x:
-45y=10x

Divide by 10:
-45/10y=x

Reduce:
-9/2y=x

4 0

3 years ago

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If f (3)=5 and f(4)=8 what does f(5) = and f(6)=

marissa [1.9K]

Answer:

f(5)=11 and f(6)=14

Step-by-step explanation:

3 0

3 years ago

How much does -8-6 equal?

nikitadnepr [17]

(-14) Hope this helps!

4 0

4 years ago

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The vertical angle to the top of a flagpole from point A on the ground is observed to be 37°11'. The observer walks 17 m directl

inysia [295]

Answer:

22m

Step-by-step explanation:

Let height of flagpole=h

AB==17 m

$\angle CAD=37^{\circ}11'=37+\frac{11}{60}=37.183^{\circ}$ (1 degree= 60 minute)

$\angle B=25^{\circ}43'=25+\frac{43}{60}=25.72^{\circ}$

We have to find the approximate height of the flagpole.

In triangle CDA,

$\frac{CD}{DA}=tan\theta=\frac{Perpendicular\;side}{Base}$

$\frac{h}{DA}=tan37.183^{\circ}$

$h=DA(0.759)$

In triangle CDB,

$tan 25.72^{\circ}=\frac{CD}{DB}$

$0.482=\frac{h}{DA+17}$

$0.482DA+8.194=h$

Substitute the value

$0.482DA+8.194=0.759DA$

$8.194=0.759DA-0.482DA$

$8.194=0.277DA$

$DA=\frac{8.194}{0.277}=29.58$

Substitute the value

$h=29.58 \times 0.759=22.45 m\approx 22m$

Hence, the height of the flagpole=22 m

3 0

3 years ago