First, find the probability of picking one 9. There are four nines in a deck of 52, so the probability is 4/52, which is 1/13.
The probability of picking a 9 the second time is 1/17, because if a 9 was picked the first time, then there are three 9s left and 51 cards left in total.
To find the probability of both events happening, multiply the individual probabilities together:
(1/13)(1/17)
The probability that both cards picked will be 9s is 1/221.
x = 3 + y Eqn(1)
y = -2x + 9 Eqn(2)
Let us solve the system of equations with the substitution method
x - 3 = y (Subtracting 3 from both sides of the Eqn(1))
Replacing y = x - 3 in Eqn (2), we have:
x - 3 = -2x + 9
x = -2x + 9 + 3 (Adding 3 to both sides of the equation)
x + 2x = 9 + 3 (Adding 2x to both sides of the equation)
3x = 12 ( Adding like terms)
x = 12/3 (Dividing by 3 on both sides of the equation)
x = 4
Replacing x=4 in Eqn(1), we have:
4 = 3 + y
4 - 3 = y (Subtracting 3 from both sides of the equation)
y=1
The answers are:
x= 4 and y=1
Answer:
well let's see below.
Step-by-step explanation:
If you're simplifying the fractional form, the answer would be f(x) + x/2 =4.
X=first number
y=second number
x=y+5
3x+2y=30
3(y+5)+2y=30
3y+15+2y=30
5y+15=30
5y=30-15
5y=15
y=3
x=3+5
x=8
B) 4.90
Hope that helped :)
