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ivolga24 [154]
3 years ago
15

In a growing number of cities, stores are required either not to make available plastic or paper bags or to do so only for an ad

ditional fee. What kind of incentive is this fee?a. Neutral b. Direct c. Complementary d. Unintended e. Indirect
Business
1 answer:
sp2606 [1]3 years ago
8 0

Answer:

The correct answer is letter "B": Direct.

Explanation:

Direct incentives are those that pursue making an immediate reaction in the audience to whom the incentive is directed. A direct incentive is usually applied when an urgent change must be made over a certain matter to avoid the exponential risks of not taking any action.

Thus, <em>the fact that in most growing cities stores are not providing plastic bags is a direct incentive to stop polluting the environment.</em>

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Which of the following statements about income taxes is not correct?
Anastaziya [24]

The correct statement regarding the income tax is Deductible temporary differences give rise to deferred tax liabilities, meaning that more tax is payable in the future. hence option C is correct

<h3>What is income tax?</h3>

A tax placed on people or organizations in relation to their income or profits is known as an income tax. Tax rates multiplied by taxable income are typically used to calculate income taxes. Tax rates might change depending on the taxpayer's attributes and source of income.

The complete part of the question is below:

A) Review Later Income tax expense includes both the amount of tax payable in the current period and the amount of tax due in future periods.

B)Income taxes are based on taxable income and not accounting income.

C)Deductible temporary differences give rise to deferred tax liabilities, meaning that more tax is payable in the future.

D)Deferred taxes arise because of temporary differences between the tax base and the carrying amount of assets and liabilities on the balance sheet.

Hence option C is correct.

Learn more about income tax:

brainly.com/question/17075354

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7 0
2 years ago
Martin Company applies manufacturing overhead based on direct labor hours. Information concerning manufacturing overhead and lab
bixtya [17]

Answer:

POAR = $29 per hour

Explanation:

<em>The overhead absorption is a per-determined rate which is used to charge overheads to production units. Note that this rate is computed using estimated figures</em>

The rate is computed as follows:

Pre-determined overhead absorption rate (POAR)

POAR = Budgeted overhead for the period/Budgeted direct labour hours

          = $145,000/5,000 labour hours

          = $29 per hour

         

5 0
4 years ago
If a seller wants to increase revenue from the sale of a product with a price elasticity of demand coefficient of 1.6, then the
Zielflug [23.3K]

It is an elastic good and to increase the revenue, the producer should decrease the price of the good.

<u>Explanation:</u>

The good that has a price elasticity of demand with a coefficient of 1.6, the good is said to have elastic demand. For such a good, the producer should decrease the price of that good to increase its revenue. With the decrease in the price, the demand of the good will increase significantly. This will help him increase his revenue.

6 0
4 years ago
Stock options are granted to the employees of Young Company on March 10, 2018. The employees must wait until March 10, 2022 to e
MAVERICK [17]

Answer:

vesting period

Explanation:

According to my research on employee stock options, I can say that based on the information provided within the question this four year waiting period is known as the vesting period. This term is defined as the amount of time it takes before shares in an employee's stock option plan unconditionally owned by the employee who holds them.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
4 years ago
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