Which number produces an irrational number when added to 0.4?<br> B. 0.444...<br> C.2/7

Can someone please help me with this 7th grade math worksheet? I will give BRANLIEST PLEASE HELP

koban [17]

Answer:

sure I'll try to help you oh math

7 0

3 years ago

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alukav5142 [94]

Most appropriate answer is
D. Histogram

4 0

3 years ago

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In isosceles △ABC the segment BD (with D∈ AC ) is the median to the base AC . Find BD, if the perimeter of △ABC is 50m, and the

Morgarella [4.7K]

Let the equal sides of the isosceles Δ ABC be x.

Given that the perimeter of Δ ABC = 50m.

Therefore, 2x + AC = 50 --- (1)

It is also given that the perimeter of Δ ABD = 40m.

Therefore, x + BD + AD = 40

BD is the median of the Δ ABC. Therefore, D is the midpoint of AC.

So AD = CD.

Or, AD = $\frac{1}{2}$ AC

Therefore, $x + BD + \frac{1}{2} AC = 40$

Multiply both sides by 2.

2x + 2BD + AC = 80

From (1), 2x + AC = 50.

Therefore, 2BD + 50 = 80

2BD = 80 - 50

2BD = 30

BD = 15m.

6 0

3 years ago

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

3 years ago

Solve the equation 3(x - 7) = 42

Effectus [21]

Answer:

x=21.

Step-by-step explanation:

First you distribute 3 to the parenthesis. You should get 3x-21=42 at this point. Then you add 21 to 42 to get 63. Here you should be at 3x=63. Divide 63 by 3 to get x=3

6 0

3 years ago

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Which number produces an irrational number when added to 0.4? B. 0.444... C.2/7