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devlian [24]
3 years ago
14

2 Points

Mathematics
1 answer:
Jobisdone [24]3 years ago
3 0
The answer is a. $11 bc you divide the amount made by the hours worked
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What.is the y intercept of a line given by the equation y=5×-21?
Delicious77 [7]

Answer:

-21

Step-by-step explanation:

If the equation of the line is

y=mx+b,

then m is the slope of the line and b is the y-intercept of the line.

In your case, the equation of the line is y=5x-21.

So, the slope of this line is m=5 and the y-intercept is b=-21.

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3 years ago
How many pairs of whole numbers have a sum of 12
MAXImum [283]
4 times 3 is 12

2 times 6 is 12
 
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Dinah went out to eat at a restaurant. She wants to leave the waitress a tip of 18%. She can determine the amount she should pay
hoa [83]

Answer:

C. 1.18b

Step-by-step explanation:

Hi! Ace here!

In order to do this, we have to convert 18% into a decimal.

The decimal form of it is .18.

So we have to do

b+.18b

Combine like terms:

1.18b

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3 years ago
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A bus covers 270km distance in 6 hours.
pentagon [3]

Answer:

(i)= 45 KPH, (ii) = 251 miles

Step-by-step explanation:

'Per' essentially means divide. Thus, to find Kilometres per hour, divide 270 by 6= 45. The bus is travelling at 45 KPH.

Then, to see how far a nine hour trip would cover, distance = speed * time =  251 miles.

7 0
1 year ago
X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
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