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Klio2033 [76]
4 years ago
8

Consider a function

7D" id="TexFormula1" title="f(x) = \frac{(1 - x)^2}{(1 + x)^2}" alt="f(x) = \frac{(1 - x)^2}{(1 + x)^2}" align="absmiddle" class="latex-formula">
Find if a given function is even odd or neither.
Mathematics
1 answer:
SCORPION-xisa [38]4 years ago
8 0

Answer:

f=

x2−2x+1

x3+2x2+x

Step-by-step explanation:

Let's solve for f.

fx=

(1−x)2

(1+x)2

Step 1: Multiply both sides by x^2+2x+1.

fx3+2fx2+fx=x2−2x+1

Step 2: Factor out variable f.

f(x3+2x2+x)=x2−2x+1

Step 3: Divide both sides by x^3+2x^2+x.

f(x3+2x2+x)

x3+2x2+x

=

x2−2x+1

x3+2x2+x

f=

x2−2x+1

x3+2x2+x

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For all the non-negative numbers, the absolute value is always equal to the actual number.

If "x" is any non-negative number, then:

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For all negative numbers, the absolute value is equal to -1 multiplied to that number.

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Absolute value of 1 is 1.
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The possible number that satisfies the given condition is 1. 


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