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diamong [38]
3 years ago
10

Angela drive 82 miles on Monday. She drove 94 miles on Tuesday. To the nearest hundred, how many miles did Angela drive over the

two days?
Mathematics
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

88 miles

Step-by-step explanation:

From the question I'm Presuming you are taking the average.

Add the two numbers together 82 + 94 = 176

Do 176 divided by 2 to get 88

You do divide by 2 because of the two days

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A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

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a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

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where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
4 years ago
Ty and Gajge are both football players who averaged 4 yards per run in yesterday’s
Anettt [7]

Answer:

The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.

Step-by-step explanation:

given that Ty and Gajge are football players.

Carries is 15 for both and average is the same 4 for both.

But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.

Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)

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The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.

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