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kherson [118]
3 years ago
14

Choose the equation that satisfies the data in the table.

Mathematics
1 answer:
White raven [17]3 years ago
3 0

Answer:

C. y = 1½x + 9

Step-by-step explanation:

The quickest way is to know what intercepts are shown here and you are done, but if you want to, then all you have to do is plug in each number given to you into each solution to confirm the authentication.

I am joyous to assist you anytime.

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141=-v-8(-8v+6) please help me!
timurjin [86]

Answer:

v=3

Step-by-step explanation:

141=-v-8(-8v+6)

distribute -8 into the parentheses

141=-v+ 64v-48

simplify by putting v's together

141=63v-48

add 48 to both sides to get x by itself  

189=63v

divide both sides to isolate x

v=3

3 0
4 years ago
Pls help me and give steps as to how to do it thank you
andrew11 [14]

Answer: x=13, y=132

Step-by-step explanation:

Using the same-side interior angles theorem, y=132.

Using the alternate interior angles theorem, 5x-17=48 \implies x=13

7 0
1 year ago
Original chess tournament evolve 64 participants the number Of participants decreased by 1/2 after each round of play. Write the
marishachu [46]

Answer:

The first three terms is 64, 32, 16

Step-by-step explanation:

Given

Number of participants = 64

Decrement = 1/2

Required

Find the first three terms

To calculate the first three terms, we make use of the following formula;

Current Term = Previous Term - 1/2 * Previous Term

The first term = Initial number of participants

First Term = 64

Second Term = First Term - 1/2 * First Term

Second Term = 64 - 1/2 * 64

Second Term = 64 - 32

Second Term = 32

Third Term = Second Term - 1/2 * Second Term

Third Term = 32 - 1/2 * 32

Third Term = 32 - 16

Third Term = 16

Hence, the first three terms is 64, 32, 16

4 0
3 years ago
Marcus can expect 1 gallon of paint to cover
Viktor [21]
D hope this helps byeeeeee
5 0
2 years ago
A ​20-ft by ​the 40-ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area of the walkway i
Jlenok [28]
<h3>Answer:  2 feet</h3>

========================================================

Explanation:

x = width of the walkway in feet

This is some positive real number.

The dimension of 20 feet bumps up to 20+2x when adding on x from both directions. Similarly, the 40 ft dimension becomes 40+2x

Refer to the diagram below.

The 20 ft by 40 ft pool is surrounded by a larger rectangle that is 20+2x ft by 40+2x ft

The pool itself is 20*40 = 800 sq ft. Add on the walkway area to get 800+256 = 1056 sq ft.

-----------

Area = length*width

1056 = (20+2x)*(40+2x)

1056 = 20*40 + 20*2x + 2x*40 + 2x*2x ... FOIL rule

1056 = 800 + 40x + 80x + 4x^2

0 = 4x^2 + 40x + 80x + 800 - 1056

0 = 4x^2 + 120x - 256

4x^2 + 120x -  256 = 0

4(x^2 + 30x - 64) = 0

x^2 + 30x - 64 = 0

Let's use the quadratic formula to finish solving for x.

Plug in a = 1, b = 30, c = -64

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-30\pm\sqrt{(30)^2-4(1)(-64)}}{2(1)}\\\\x = \frac{-30\pm\sqrt{1156}}{2}\\\\x = \frac{-30\pm34}{2}\\\\x = \frac{-30+34}{2} \ \text{ or } \ x = \frac{-30-34}{2}\\\\x = \frac{4}{2} \ \text{ or } \ x = \frac{-64}{2}\\\\x = 2 \ \text{ or } \ x = -32\\\\

Recall we made x be positive. This is because a negative walkway width does not make sense. This means we'll ignore x = -32.

The only practical solution is x = 2

Therefore, the walkway is <u>2 feet wide</u>

4 0
2 years ago
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