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Zigmanuir [339]
3 years ago
6

Name the hydrocarbon ch3(ch2)3ch3

Chemistry
2 answers:
Serjik [45]3 years ago
7 0

C4H10 CH3CH2CH2CH3 or CH3(CH2)2CH3 Butane

levacccp [35]3 years ago
7 0

Answer: pentane

Explanation:

- The IUPAC nomenclature of organic molecules is based on the longest carbon chain in the molecule.

- Among the basic categories of organic compounds are Alkanes (all bonds are single), Alkenes (double bond exists) and Alkynes (triple bond exists).

- We must add certain prefixes for the number carbon atoms in the molecule accordingly.

- We must add certain suffixes for the type (category) of the molecule accordingly.

- This molecule can be written elongated as, CH3CH2CH2CH2CH3.

- If we have five carbon atoms in the organic molecule, we add the prefix (pent-).

- If the type of molecule is Alkane, we add the suffix (-ane).

Hence, the IUPAC name of this compound is pentane..


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<u>Answer:</u>

<u>For a:</u> The standard Gibbs free energy of the reaction is -347.4 kJ

<u>For b:</u> The standard Gibbs free energy of the reaction is 746.91 kJ

<u>Explanation:</u>

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}           ............(1)

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The given chemical equation follows:

2Ce^{4+}(aq.)+3I^{-}(aq.)\rightarrow 2Ce^{3+}(aq.)+I_3^-(aq.)

<u>Oxidation half reaction:</u>   Ce^{4+}(aq.)\rightarrow Ce^{3+}(aq.)+e^-       ( × 2)

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  • <u>For b:</u>

The given chemical equation follows:

6Fe^{3+}(aq.)+2Cr^{3+}+7H_2O(l)(aq.)\rightarrow 6Fe^{2+}(aq.)+Cr_2O_7^{2-}(aq.)+14H^+(aq.)

<u>Oxidation half reaction:</u>   Fe^{3+}(aq.)\rightarrow Fe^{2+}(aq.)+e^-       ( × 6)

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