Answer:
yes
no
no
yes
Explanation:
<h2>ch4(g)+2o2(g)=Cos(g)+2h2o(g)</h2>
Answer:
Charge is conserved due to the groups in which Lithium and Chlorine are located in the periodic table of the elements.
Explanation:
In the reaction 
, we can examine the groups in which Li and Cl are found in the periodic table of the elements. Lithium appears in Group 1A, or the alkali metals group, indicating that it carries a charge of +1. Chlorine appears in Group 7A, or the halogen group, indicating that it carries a charge of -1. Because LiCl's constituent elements carry the same charges as previously mentioned, LiCl will have an overall charge of 0.
The chemical equation can then be rewritten as 
, which, if looking at the individual charges of Li and Cl in lithium chloride, becomes 
. Adding the charges on the reactant and product sides of this chemical equation gives us zero in both locations, meaning that we have a charge of 0 on the reactant side and a charge of 0 on the product side. This indicates that charge is conserved in this reaction.
Another way to look at this is expressed in the valence electrons of Li and Cl. Li has an electron configuration of 
, where the n = 2 electron shell has one of eight total electrons needed to fill the valence shell. This means that Li will easily lose one electron in order to have an electron configuration where the n = 1 electron shell is full, 
, and become the 
ion. Similarly, Cl has an electron configuration of 
(or ![[Ne]3s^{2}3p^{5}](https://tex.z-dn.net/?f=%5BNe%5D3s%5E%7B2%7D3p%5E%7B5%7D)
), meaning that the n = 3 electron shell is one electron away from becoming complete. Cl will easily gain one electron to have the electron configuration ![[Ne]3s^{2}3p^{6}](https://tex.z-dn.net/?f=%5BNe%5D3s%5E%7B2%7D3p%5E%7B6%7D)
(or ![[Ar]](https://tex.z-dn.net/?f=%5BAr%5D)
) in order to have an electron configuration where the n = 3 electron shell is full, 
, and become the 
ion. Thus, when Li and Cl bond, Li will lose the electron ![[1, 0, 0, +\frac{1}{2}]](https://tex.z-dn.net/?f=%5B1%2C%200%2C%200%2C%20%2B%5Cfrac%7B1%7D%7B2%7D%5D)
and transfer it to Cl, where it will become the electron ![[3, 1, 1, -\frac{1}{2}]](https://tex.z-dn.net/?f=%5B3%2C%201%2C%201%2C%20-%5Cfrac%7B1%7D%7B2%7D%5D)
, thus conserving charge, as there is an equal total number of electrons before and after the reaction.
Answer: The Ionization energy of Barium is lower and hence it can lose its electrons easily.
Explanation:
Ionization energy is defined as the energy required to remove an electron from an isolated gaseous atom. It is represented as 
This energy will be higher for fully filled and half-filled electronic configuration than partially filled electronic configuration. This is so because half filled and fully filled configurations are stable.
Magnesium is the 12th element of the periodic table having electronic configuration of = ![[Ne]3s^2](https://tex.z-dn.net/?f=%5BNe%5D3s%5E2)
Barium is the 56th element of the periodic table having electronic configuration of ![[Xe]6s^2](https://tex.z-dn.net/?f=%5BXe%5D6s%5E2)
Both magnesium and barium belong to the same group as they have similar valence electrons. But as Barium is larger in size, the valence electrons lie farther from the nucleus and lesser energy is required to remove the electron and thus ionization energy will be lower for barium and thus will be more reactive.
Answer:
1:Natural selection
2: competition
Natural selection; the process by which organisms with variations most suited to their local environment survive and leave more offspring.
Competition: The struggle between organisms to survive in a habitat with limited resources (food, water, shelter)
