To start to solve this problem, we need to know what vertex form is. The vertex form of a parabola is. The vertex form of a parabola is a(x-h) + k, where k is the vertical shift, h is the horizontal shift, and a is the value that tells the stretch.
To start to solve this equation, we want to start to create a difference of two squares.
y = 2(x²+
x) We do this step to make the x² have a coefficient of 1
Now, we want to complete the square. To complete the square, we take 1/2 of the coefficient of x, and then square that.
1/2 * 1/2 = 1/4, and 1/4²=1/16
That means that we need to add 1/16 inside and outside the parenthesis.
We get:
y = 2(x²+1/2x + 1/16) - 1/16*2
We do -1/16*2 on the outside because since we added it inside the parenthesis, we need to take it away somewhere else (if that makes sense). The two is there because there is a two in front of the parenthesis.
We get:
y = 2(x+1/4)² - 1/8, by completing the square and simplifying, and this is the final answer.
Answer:
x = 
Step-by-step explanation:
According to Pythagorean Theorem, the square value of hypotenuse is equal to sum of square value of two legs:
x^2 + 4^2 = 10^2
x^2 + 16 = 100 subtract 16 from both side
x^2 = 84 find the root of both sides
x =
Answer:
- f'(1) exists: f'(1) = -2
- f'(0) DNE
Step-by-step explanation:
<h3>a)</h3>
The function is continuous for x > 0 . The derivative is defined on that interval and is equal to ...
f'(x) = -2x . . . . . for x > 0
Then at x = 1, the derivative is ...
f'(1) = -2(1)
f'(1) = -2
__
<h3>b)</h3>
The function has a jump discontinuity at x=0, so the derivative does not exist at that point. A condition for the existence of the derivative is that the function is continuous at the point of interest.
It should be 5 because that's the smallest number and A is the first point
The given coordinates are:
p1: (12,4) and p2: (-8,8)
Th x coordinate of the midpoint is calculated as follows:
Xmidpoint = (x1+x2) / 2 = (12+-8) / 2 = 4/2 = 2
The y coordinate of the midpoint is calculated as follows:
Ymidpoint = (y1+y2) / 2 = (4+8) / 2 = 12/2 = 6
Based on the above calculations, the midpoint of the segment with the given coordinates is (2,6)
