Step-by-step explanation:
Q1 . (f+g)(x) = f(x) + g(x)
=4x-4 +2x^2 -3x
= 2x^2 + x -4
Q2. (f-g)(x) = f(x) - g(x)
= 2x^2−2 - (4x+1)
= 2x^2 -2 -4x -1
= 2x^2 - 4x -3
Q3. h(x)=3x−3 and g(x)=x^2+3
(h.g)(x) = h(x) × g(x)
= (3x-3) × (x^2 + 3)
=3x^3 -3x^2 + 9x -9
Q4.f(x)=x+4 and g(x)=x+6
(f/g)(x) = f(x) ÷ g(x)
= x+4 / x+6
the domain restriction is x>-6
x<-6
x doesn't equal (-6)
The answer is b I believe
Answer:
x<10
Step-by-step explanation:
Add '-7' to each side of the equation.
7 + -7 + -0.3x = 4 + -7
Combine like terms: 7 + -7 = 0
0 + -0.3x = 4 + -7
-0.3x = 4 + -7
Combine like terms: 4 + -7 = -3
-0.3x = -3
Divide each side by '-0.3'.
x = 10
Simplifying
x = 10
Answer:
step 2
Step-by-step explanation:
The student first made an error in the step 2.
Because if we simplify the equation A in step 1, we should distribute the right side of the equation following the rule a(b-c) = a*b +a*(-c)
So, it would be
–7y = (-7)*(16)+(-7)*(-2z)
=> -7y = -112 + 14z
