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trapecia [35]
3 years ago
14

5TH GRADE MATH TESTING PEOPLE​

Mathematics
2 answers:
Leviafan [203]3 years ago
6 0
It is 23.917 because 51.92-28.003= to that number
Gemiola [76]3 years ago
5 0

28.003 is the answer because it is the closest to zero.

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
Contact [7]

Answer:

\dfrac{z-y}{a+b}

Step-by-step explanation:

Given expression:

\dfrac{z^2-y^2}{a^2-b^2}\div \dfrac{z+y}{a-b}

Substitute

a^2-b^2=(a-b)(a+b)\\ \\z^2-y^2=(z-y)(z+y)

into the expression:

\dfrac{(z-y)(z+y)}{(a-b)(a+b)}\div \dfrac{z+y}{a-b}\\ \\ \\=\dfrac{(z-y)(z+y)}{(a-b)(a+b)}\times \dfrac{a-b}{z+y}\\ \\ \\=\dfrac{z-y}{a+b}

4 0
4 years ago
Read 2 more answers
Someone make me smile
Reil [10]
Your doing your best in school keep it upp !
4 0
3 years ago
Read 2 more answers
Find all possible values of α+
const2013 [10]

Answer:

\rm\displaystyle  0,\pm\pi

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =  \tan( \alpha )  \tan( \beta )  \tan( \gamma )  -  \tan( \gamma )

factor out tanγ:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =   \tan( \gamma ) (\tan( \alpha )  \tan( \beta ) -  1)

divide both sides by tanαtanβ-1 and that yields:

\rm\displaystyle   \tan( \gamma ) =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{ \tan( \alpha )  \tan( \beta )    - 1}

multiply both numerator and denominator by-1 which yields:

\rm\displaystyle   \tan( \gamma ) =   -  \bigg(\frac{ \tan( \alpha )  +  \tan( \beta ) }{ 1 - \tan( \alpha )  \tan( \beta )   } \bigg)

recall angle sum indentity of tan:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( \alpha  +  \beta )

let α+β be t and transform:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( t)

remember that tan(t)=tan(t±kπ) so

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm k\pi )

therefore <u>when</u><u> </u><u>k </u><u>is </u><u>1</u> we obtain:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm \pi )

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha  -\beta\pm \pi )

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm \pi

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ \pm \pi  }

<u>when</u><u> </u><u>i</u><u>s</u><u> </u><u>0</u>:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta \pm 0 )

likewise by Opposite Angle Identity we obtain:

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha   -\beta\pm 0 )

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm 0

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ 0  }

and we're done!

8 0
3 years ago
Read 2 more answers
The ratio of a to b is 2:3, and the ratio of a to c is 3: 10. What is the ratio of b to c?
Stolb23 [73]

Answer: 3:10

Step-by-step explanation:

From the question, b= 3; c=10

Ratio of b:c will be

the value of b:value of c

=3:10

I hope you understand

4 0
3 years ago
Read 2 more answers
I WILL GIVE BRAINLIEST<br> Answer must be simplified<br> 4x ≤ 12
alina1380 [7]

Answer:   x ≤ 3

Step-by-step explanation:

4x ≤ 12

divide each side by 4

x≤3

8 0
3 years ago
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