Answer:
Explanation:
Energy of system of charges
= k q₁q₂ / r₁₂ + k q₁q₃ / r₁₃ + k q₃q₂ / r₃₂
q₁ , q₂ and q₃ are charges and r₁₂ , r₁₃ , r₃₂ are densities between them
9 x 10⁹ ( 2x2 x10⁻¹²/ .25 + 2x2 x10⁻¹²/ .25 + 2x2 x10⁻¹²/ .25 )
= 9 x 10⁹ x 3 x 16 x 10⁻¹²
= 432 x 10⁻³
= .432 J .
Option D is correct. The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr
Speed is a body is defined as the ratio of the distance with respect to the time taken by the body. Mathematically:
Speed = Distance/Time
GIven the following
Distance = 104km/hr
If it is 6:00 p.m. in New York, it is 7:00 a.m. of the next day of the week in Tokyo, this means that the time difference between New York and Tokyo is 11 hours.
Time = -11 hours
Get the required speed
Speed = 104/-11
Speed = -9.454545
Speed = -10km/hr
The speed at which the earth's surface moves because of the earth's rotation will then be equivalent to -10³ km/hr
Learn more here: brainly.com/question/2583051
I think it is False because as the Gad relajases fuel it doesn’t move as much anymore
Answer: The ratio of atoms of potassium to ratio of atoms of oxygen is 4:2
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed, and remains conserved. The mass of products must be same as that of the reactants.
Thus the number of atoms of each element must be same on both sides of the equation so as to keep the mass same and thus balanced chemical equations are written.
K exists as atoms and oxygen exist as molecule which consists of 2 atoms. The ratio of number of atoms on both sides of the reaction are same and thus the ratio of atoms of potassium to ratio of atoms of oxygen is 4:2.
Answer:
The charge resides on the outer surface =
C
Explanation:
Surface area of cell 
Separation between two plate
Dielectric constant 
Potential difference 
The capacitance of parallel plate capacitor in free space is given by,

Where
permittivity of free space = 
The Capacitance of capacitor is increase by
times when it placed in dielectric medium.

And we know that, 
So charge on the outer surface is given by,


