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masya89 [10]
3 years ago
11

1. Which of the following is true about ecology? (1 point)

Biology
1 answer:
mojhsa [17]3 years ago
3 0
The statement that is true about ecology is that ecology is an area of study that focuses on interactions in nature. The best way for an ecologist to determine the effects of an industrial waste on a species of fish would be to <span>conduct experimental work in a lab. Ecosystems, populations and communities are related because: </span><span>An ecosystem consists of a community of organisms and its physical environment, and a community is made up of many different populations of organisms.</span>
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A cross between black a chicken (BB) and a white chicken (WW) produces offspring that
alisha [4.7K]

Answer:

The answer is codominace. :)

Explanation:

6 0
3 years ago
What is the role of alveoli in respiration
Burka [1]

Answer:

<em>What is the role of alveoli in respiration ⇔ Alveoli are the place where the exchange of gases takes place. The outer part of alveoli has blood vessels. These vessels are carrying Co2 rich blood to exchange at the alveoli. The O2 from the alveoli is diffused into the blood while co2 is sent into the lungs. That O2 rich blood is then carried to heart to pump it to the whole body. and this process continues. </em><em>The alveoli are where the lungs and the blood exchange oxygen and carbon dioxide during the process of breathing in and breathing out.</em>

Explanation:

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<u><em>I hope this helps and have a good day!</em></u>

5 0
1 year ago
How are eukaryotic cells different from prokaryotic cells?
avanturin [10]

Answer:

Prokaryotic cell:

Prokaryotic cell do not have the nucleus and their DNA is present in the cytoplasm. The membrane bound cell organelle are absent in the prokaryotic cells. The ribosome of prokaryotic cell is 70'S. Transcription and translation is coupled in prokaryotic cells.

Eukaryotic cells:

Eukaryotic cell have well defined nucleus and their DNA is present inside the nucleus. The membrane bound cell organelle are present in the eukaryotic cells. The ribosome of eukaryotic cell is 80'S. Transcription and translation is not coupled and takes place in separate compartments in eukaryotic cells.

4 0
3 years ago
Explain how we know that DNA breaks and rejoins during recombination.
alisha [4.7K]

Answer:

It occurs through homologous recombination

Explanation:

GENERAL RECOMBINATION OR HOMOLOGIST

           Previously we defined its general characteristics. We will now describe a molecular model of this recombination, based on the classic Meselson and Radding, modified with the latest advances. Do not forget that we are facing a model, that is, a hypothetical proposal to explain a set of experimental data. Not all points of this model are fully clarified or demonstrated:

           Suppose we have an exogenote and an endogenote, both consisting of double helices. In recombination models, the exogenote is usually referred to as donor DNA, and the endogenote as recipient DNA.

1) Start of recombination: Homologous recombination begins with an endonucleotide incision in one of the donor double helix chains. Responsible for this process is the nuclease RecBCD (= nuclease V), which acts as follows: it is randomly attached to the donor's DNA, and moves along the double helix until it finds a characteristic sequence called c

Once the sequence is recognized, the RecBCD nuclease cuts to 4-6 bases to the right (3 'side) of the upper chain (as we have written above). Then, this same protein, acting now as a helicase, unrolls the cut chain, causing a zone of single-stranded DNA (c.s. DNA) to move with its 3 ’free end

2) The gap left by the displaced portion of the donor cut chain is filled by reparative DNA synthesis.

3) The displaced single chain zone of the donor DNA is coated by subunits of the RecA protein (at the rate of one RecA monomer per 5-10 bases). Thus, that simple chain adopts an extended helical configuration.

4) Assimilation or synapse: This is the key moment of action of RecA. Somehow, the DNA-bound RecA c.s. The donor facilitates the encounter of the latter with the complementary double helix part of the recipient, so that in principle a triple helix is formed. Then, with the hydrolysis of ATP, RecA facilitates that the donor chain moves to the homologous chain of the receptor, and therefore matches the complementary one of that receptor. In this process, the chain portion of the donor's homologous receptor is displaced, causing the so-called "D-structure".

It is important to highlight that this process promoted by RecA depends on the donor and the recipient having great sequence homology (from 100 to 95%), and that these homology segments are more than 100 bases in length.

Note that this synapse involves the formation of a portion of heteroduplex in the double receptor helix: there is an area where each chain comes from a DNA c.d. different parental (donor and recipient).

5) It is assumed that the newly displaced chain of the recipient DNA (D-structure) is digested by nucleases.

6) Covalent union of the ends originating in the two homologous chains. This results in a simple cross-linking whereby the two double helices are "tied." The resulting global structure is called the Holliday structure or joint.

7) Migration of the branches: a complex formed by the RuvA and RuvB proteins is attached to the crossing point of the Holliday structure, which with ATP hydrolysis achieve the displacement of the Hollyday crossing point: in this way the portion of heteroduplex in both double helices.

8) Isomerization: to easily visualize it, imagine that we rotate the two segments of one of the DNA c.d. 180o with respect to the cross-linking point, to generate a flat structure that is isomeric from the previous one ("X structure").

9) Resolution of this structure: this step is catalyzed by the RuvC protein, which cuts and splices two of the chains cross-linked at the Hollyday junction. The result of the resolution may vary depending on whether the chains that were not previously involved in the cross-linking are cut and spliced, or that they are again involved in this second cutting and sealing operation:

a) If the cuts and splices affect the DNA chains that were not previously involved in the cross-linking, the result will be two reciprocal recombinant molecules, where each of the 4 chains are recombinant (there has been an exchange of markers between donor and recipient)

b) If the cuts and splices affect the same chains that had already participated in the first cross-linking, the result will consist of two double helices that present only two portions of heteroduplex DNA.

8 0
3 years ago
A heterozygous gray (two genes are involved) cat is crossed with a cat that is heterozygous for these two genes. What is the pro
romanna [79]

Answer:50% chance, and the genotype would be heterozygous

Explanation:

G=gray r=black

      G     r

G   GG   Gr

r     Gr    rr

3 0
2 years ago
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