Important muscle electrical signals is the movement of charged material (ions) across cellular membranes in a limited area
Answer:
BbxBb.
Explanation:
If Bb gene is crossed with Bb, the offspring is produced with normal hearing because both the genes are recessive in which the deafness gene hide and the hearing gene is dominant so the offspring can hear sounds clearly. The dominant A gene is responsible for deafness and we can see the offspring BbxBb in which no dominant gene is present. The other three offspring are deaf because of the presence of dominant A gene in their genetic makeup.
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<em><u>i think this could help :) </u></em>
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<em><u>Count the number of cells in each phase of mitosis. Add the data to the table on page 4. Calculate the percentage of cells in in each phase of mitosis. Step 2: Calculate the time an onion root tip cell spends in part of the cell cycle. </u></em>
Answer:
- If they have one child, the probability that he or she will be affected is 1/4.
- If they have two children, the probability that at least one of them will be affected is 7/16.
Explanation:
A cross between two heterozygous Aa individuals will produce the followinf offspring: 1/4 AA, 2/4 Aa and 1/4 aa.
Since the disease is recessive, 1/4 of the offspring will have the <em>aa </em>genotype and 3/4 of the offspring will be unaffected.
Every time they have children new gametes were generated <u>independently</u>.
The probability of having <u>no</u> affected children both times is, according to rules of probability for independent events, 3/4 × 3/4 = 9/16 (it's the probability of having a healthy child the first time multiplied by the probability of having a healthy child the second time).
The probability of having at least one affected child is 1 - probability of no affected children = 1 - 9/16 = 7/16.