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son4ous [18]
4 years ago
9

Can someone help me with my math plzzzzzzz i just need someone to go over stuff with me plz

Mathematics
1 answer:
Lera25 [3.4K]4 years ago
4 0
Do you have gmail hangouts? We can go over all of it and send pictures/screenshots of it as well if you want to. I'm here.
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How much are these coins worth???
ser-zykov [4K]

Answer

3.26$

Step-by-step explanation:

5 0
3 years ago
Kara mixes different colors of paint to create new colors. The table shows the amount of paint Kara mixes per batch.
Sergio [31]

Answer:

D. Batch 5.

Step-by-step explanation:

The batch should have the same proportion of blue to white to yellow.

In Batch 1, there are two parts of blue, 1.5 parts of white, and 1 part of yellow.

In Batch 5, there are four parts of blue, 3 parts of white, and 2 parts of yellow.

4 / 2 = 2

3 / 2 = 1.5

2 / 2 = 1

Since the proportions are equal to those found in Batch 1, D. Batch 5 will create the same colors as the first batch.

Hope this helps!

8 0
4 years ago
Line m includes the points (-5,3) and (-2,-6). Line n has the same slope as line m and a y intercept of -2/3. Write the equation
KIM [24]
Slope intercept form is y =mx+b. To find your slope since you already know the y-intercept you how to subtract y2-y1 over x2-x1. That is -6-(3) over -2-(-5) but for -2-(-5) you have to keep change change and you'll get 3. then find what -6-(3) is and you have your slope, so just plug it into the equation.
8 0
3 years ago
What does the line 5x 2y = 8 look like?
Arturiano [62]
It's going to be a positive slope line so I would say from left to right top left to bottom right. Good luck!
6 0
3 years ago
The function h represents the height of an object t seconds after it is launched into the air. The function is
nasty-shy [4]

Step-by-step explanation:

h(t) = -5t² + 20t + 18

this is a parabola (the curve an object follows when thrown up into the air and then falling back down).

and as such it will most likely have 2 solutions (one for when going up, and one for when falling back down again).

33 = -5t² + 20t + 18

15 = -5t² + 20t

-3 = t² - 4t

t² - 4t + 3 = 0

the solution of such a quadratic equation is

t = (-b ±sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -4

c = 3

t = (4 ±sqrt(16 - 4×1×3))/(2×1) = (4 ±sqrt(16-12))/2 =

= (4 ±sqrt(4))/2 = (4 ± 2)/2

t1 = (4+2)/2 = 6/2 = 3

t2 = (4-2)/2 = 2/2 = 1

the object reaches the height of 33 m first after 1 second (while going up), and then again after 3 seconds (while falling down again).

7 0
2 years ago
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