Option B. 13π/6 and Option D. 5π/6
To get the reference angle π/6 for the given angles we will check each angle given in the options.
A. 8π/6
Since 8π/6 means 240° which lies in 3rd quadrant. Therefore reference angle of 240°= 240-180 = 60° or π/3
B. 13π/6
13π/6 means 390° which lies in first quadrant.
Therefore reference angle = 390-360 = 30° or π/6
C. 3π/6
Since 3π/6 means 90° therefore reference angle of 90° is the same as 90°.
Or the reference angle is = π/2
D. 5π/6
5π/6 means angle is 150° which lies in second quadrant therefore reference angle of 150° = 180-150 = 30° or π/6
answer is Option B and D.
Draw a picture of a building and a one mile (or 5280 feet) distance to a point from the base of the building.
The angle of elevation is given as 11° and we want the height of the building or x.
tan(11°) = x/5280
5280 tan(11°) = x
1026.3 feet = x
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
Answer:
3(x^2 x Y)(4z x X)(2y x Z)
Step-by-step explanation:
A function is a rule that assigns exactly one output to a given input. The input is taken from a set called the domain, and the corresponding output belongs to a set called the range.
1. In this exercise, we're calling the pool of patients 1-8 the domain, and the pool of nurses A-D the range. The given table describes a function because any patient is assigned to only one nurse.
2. This wouldn't be a function if at least one patient was assigned to more than one nurse. If this were to happen in practice, the patient could be, say, given the same dose of some medicine twice if the nurses aren't careful.
3. Making the nurse pool the domain and the patient pool the range would give a relation that is not a function, since more than one patient is assigned to one nurse.
Answer:
FALSE
Step-by-step explanation:
<E in ∆AED ≅ <E in ∆CEB.
Both are 90°.
Side ED ≅ Side EB
Side AD ≅ Side CB.
Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.
