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liraira [26]
4 years ago
6

Wendy can wash a car twice as fast as Jason. When they work together, Wendy and Jason can wash a large van in 2 hours. How many

hours would it take Jason to wash the van by himself?
Mathematics
1 answer:
Ugo [173]4 years ago
5 0
X= number of hours would it take Jason to wash the van by himself.
2x=number of hours would it take Wendy to wash the van by herserlf.

<span>we calcaulate the fraction of  work by Jason during one hour </span>

x hours-----------------------------1 work
1 hour----------------------   fraction of work during one hour.

fraction of work during one hour=(1 hour * 1work) / x hours=1/x


we calculate the fraction of work by Wendy during one hour.
2x hours-----------------------------1 work
1 hour----------------------   fraction of work during one hour.

fraction of work during one hour=(1 hour * 1work) / 2x hours=1/2x

We can suggest this equation:
2 hours(fraction of work by Jason during one hour + fraction of work by Wendy during one hour)=1 work

2(1/x + 1/2x)=1

least common multiple=2x
2(2+1)=2x
2(3)=2x
6=2x
x=6/2
x=3

answer: 3 hours would ti take Jason to wash the van by himself.


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To determine the length of CD, the first step is to determine the coordinates of both endpoints from the graph

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Replace the coordinates on the formula using C(2,-1) as (x₁,y₁) and D(-1,-2) as (x₂,y₂)

\begin{gathered} d_{CD}=\sqrt[]{(2-(-1))^2+((-1)-(-2))}^2 \\ d_{CD}=\sqrt[]{(2+1)^2+(-1+2)^2} \\ d_{CD}=\sqrt[]{3^2+1^2} \\ d_{CD}=\sqrt[]{9+1} \\ d_{CD}=\sqrt[]{10} \end{gathered}

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Answer:

The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.

The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.

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MATH QUADRATIC FORMULA

Kyle C. asked • 05/05/16

The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.

The length of a rectangle is 3” more than twice the width. The area of the rectangle is 150 in^2. Find the dimensions of the rectangle.

ANSWER

ABOUT THIS TUTOR ›

We know that Area = Length x Width

in this case, L = 2W + 3 and A = 150in2

so, 150in2 = W x (2w + 3)

150in2 = 2W2 + 3W

rearranging, 2W2 + 3W - 150in2 = 0

we need to use the quadratic formula to solve this equation

that formula is [-b±(√b2 -4ac)]/2a

a = 2, b = 3, c = -150

inserting those values, we get [-3±(√32 -4•2•-150)]/2•2

which becomes (-3±√1209)/4

we get (-3 ± 34.771)/4

we can discard the negative value, because no length can be negative

so, W ≅ 7.942 inches

then L = 2W + 3 ≅ 18.886 inches

Proof: 7.942in x 18.886in ≅ 149.99

HOPE IT'S HELPFUL

THANK YOU

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Answer:

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