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mezya [45]
3 years ago
13

Before making invitations, Katrina counted the supplies she bought for her party.

Mathematics
2 answers:
aleksandrvk [35]3 years ago
5 0
The GCF of 36 and 81 is 9

36/9 = 4 water balloons
81/9 = 9 beads

Katrina can invite 9 friends, with each getting 4 water balloons and 9 beads
ale4655 [162]3 years ago
3 0

Answer:

C. 9

Step-by-step explanation:

9 is the largest number that can fit into both 36 and 81 without a remainder.

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6 0
3 years ago
The sum of the two decimals is 1 the product of these decimals is 0.25 the quotient of these two decimals is 1 what are the two
ExtremeBDS [4]
Since the quotient of the two decimal numbers is 1, that tells use that they are the same number.
Since the sum of the two numbers equals 1 and both numbers are the same, then the answer must be 1 divided by 2. or .5
the fractions would be 1/2 and 1/2

5 0
3 years ago
the temperature outside changed from 85 degrees Fahrenheit to 49 degrees fahrenheit over a period of six days
Mice21 [21]

Answer:

whats the ?

Step-by-step explanation:

4 0
3 years ago
If f(x) equals x/2+8 what is f(x) when x=10
Sphinxa [80]

Answer:

13

Step-by-step explanation:

Since we want to find f(x) when x equals 10, we can substitute 10 in for x

f(x)=x/2 +8

f(10)=10/2+8

Divide 10 by 2

f(10)=5+8

Add 5 and 8

f(10)=13

So, f(x) when x=10 is 13

4 0
3 years ago
Read 2 more answers
You know that a rope is no more than 150 feet long. You need to cut the rope into 3 pieces.
Sunny_sXe [5.5K]

Answer:

80 ft

Step-by-step explanation:

<em>hey there,</em>

<em />

< We know that the rope is 3 pieces long. To make this into an equation, let's just write x + y + z = 150.

Assuming "y" is our second piece, we can tell y = 2x, because it is two times the size of the first piece, which is "x". We also know "z" (our third piece): z = 30.

We can try inputting all the things we know now. x + (2x) + 30 = 150. From here, we can find that x = 40. Since y is our second piece, y = 2x, so 2 x (40) = 80. The second piece would be 80 feet long. >

<u>Hope this helped! Feel free to ask anything else.</u>

7 0
3 years ago
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