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Usimov [2.4K]
4 years ago
12

Whats 5/6 + 1/2 plz i am a starter​

Mathematics
2 answers:
kodGreya [7K]4 years ago
4 0

Answer:

1 1/3

Step-by-step explanation:

First, you have to find like denominators (denominators that are the same). Since 6 is a multiple of 2, you can leave the 5/6 as it is and only have to change the 1/2.

3 x 2 = 6

Since 3x2 is 6, multiply the 1 by 3 as well.

And you get: 3/6

Now you can add the two fractions.

5/6 + 3/6 = 8/6  *Always remember you only have to add the numerators, not the denominators!

Now you have to simplify (depends on the instructions you receive).

Since 6 goes into 8 once, you get 1, and still have 2/6 left over. You can still simplify 1 2/6 to 1 1/3. (Because 2 can go into itself once and 3 times, which results in 1/3.)

So the answer is 1 1/3.

Firdavs [7]4 years ago
3 0
In exact form it would be 4/3
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If we multiply a positive and a negative number, is the result positive or<br> negative?
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Step-by-step explanation:

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Ambitious

x+5y=12

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4 years ago
What are the zeros of the quadratic function f(x) = 6x2 + 12x - 7?<br>​
mina [271]

Answer:

\frac{-6+\sqrt{78} }{6} and \frac{-6-\sqrt{78} }{6}

Step-by-step explanation:

We are asked that what are the zeros of the quadratic function f(x) = 6x² +12x -7.

So, we have to find the roots of the equation, f(x) = 6x² +12x -7 =0 ...... (1)

Since the quadratic function can not be factorized, so we have to apply Sridhar Acharya's formula.

This formula gives if, ax² +bx +c =0, the the two roots of the equation are

\frac{-b+\sqrt{b^{2}-4ac } }{2a} , \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Therefore, in our case 'a' being 6, 'b' being 12 and 'c' being -7, the two roots of the equation (1) will be

\frac{-12+\sqrt{12^{2}-4*6*(-7) } }{2*6},  \frac{-12-\sqrt{12^{2}-4*6*(-7) } }{2*6}

= \frac{-12+\sqrt{312} }{12},\frac{-12-\sqrt{312} }{12}

=\frac{-6+\sqrt{78} }{6} and \frac{-6-\sqrt{78} }{6}

Hence, x= \frac{-6+\sqrt{78} }{6}

and x= \frac{-6-\sqrt{78} }{6}

(Answer)

9 0
4 years ago
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\mathsf\blue{♧ANSWER♧}

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\mathsf \green{ \frac{8 \times 12}{2} }

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\mathsf \green{48 \: square \: units}

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