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jenyasd209 [6]
3 years ago
15

Find the fifth term in the geometric sequence for a1=2 and r=3

Mathematics
1 answer:
leonid [27]3 years ago
6 0

D=4Step-by-step explanation:

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There were 640 gallons of water in a 1,600-gallon pool. Water is being pumped into the pool at a rate of 320 gallons per hour.
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Answer:

4

Step-by-step explanation:

do 320 +320 untill you get to 1,600  

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If i but a round wall clock and if the radius is 10m what is the circumference of the clock? ?
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Circumference of circle= 2*idonthaveapisymbol*r 2pir Or Pi x diameter = 3.14 * 20 2(3.14)(10)
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Help!
lord [1]

Answer:

  1

Step-by-step explanation:

The square of the value in the empty space is the constant in the expanded expression. That is ...

  [ ]² = 1

The value in the space is ...

  [ ] = √1 = 1

The filled-in equation is ...

  (3x -1)² = 9x² -6x +1

_____

The expansion of the square of a binomial is ...

  (ax -b)² = a²x² -2abx +b²

Above, we used the constant term to find 'b', but we could also have used the linear term:

  -6x = -2(3)bx . . . . . a=3 in this problem

  1 = b . . . . . . . divide by -6x

6 0
3 years ago
How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
-BARSIC- [3]
The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
b^{2}=121
b=11

Hence the limit of the area under g(x) is between a=1 and b=11

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3 years ago
Which of the following can be represented by coordinates x comma y?
raketka [301]
There is not anything to use to answer with. i cannot provide any information to help since there is nothing to use
4 0
3 years ago
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