For 4x^2y over 2x^8y^4 try 2 over x^6y^3
Answer:
true
Step-by-step explanation:
a square will always be a rectangle but a rectangle will not always be a square.
The answer is 13.1111111111. Hope this helps!
Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>
Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call quarters, nickels and dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation
There are 5 nickels.
Now, we use this value to find the number of quarters
There are 13 quarters.
Also,
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.
I have my work at the bottom but to explain you have to divide 30/12, and I got 2.5. That means 30 is 2.5 times bigger than 12. Because we have to find x, we have to divide 7/2.5, to find what is 2.5 times smaller than 7. That’s 2.8. So, x= 2.8