Ted is not particularly creative. He uses the pickup line "If I could rearrange the alphabet, I'd put U and I together." The
1 answer:
Answer:
No, the sum of all the probabilities is not equal to 1.
Step-by-step explanation:
Given
Required
Determine if the given parameter is a probability distribution
For a probability distribution to exist, the following must be true;
So, we have:
<em>Hence, it is not a probability distribution because the sum of all probabilities is not 1</em>
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ANSWER
B.Yes, f is continuous on [1, 7] and differentiable on (1, 7).
EXPLANATION
The given
The hypotheses are
1. The function is continuous on [1, 7].
2. The function is differentiable on (1, 7).
3. There is a c, such that:
This implies that;
Since the function is continuous on [1, 7] and differentiable on (1, 7) it satisfies the mean value theorem.
B.Yes, f is continuous on [1, 7] and differentiable on (1, 7).
EXPLANATION
The given
The hypotheses are
1. The function is continuous on [1, 7].
2. The function is differentiable on (1, 7).
3. There is a c, such that:
This implies that;
Since the function is continuous on [1, 7] and differentiable on (1, 7) it satisfies the mean value theorem.