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frosja888 [35]
3 years ago
7

Mr. Wells tells his class of 24 that when they completed the assignment, they may play online math games. At the end of class, 4

0% of the class is playing online math games. Approximately how many students still need to complete their assignmnet?
Mathematics
1 answer:
QveST [7]3 years ago
3 0

Hello there! Your answer is approximately 14 students.

To solve this question, you want to start by finding 40% of 24. To do this, convert 40% into a decimal (divide by 100) and multiply by 24.

24 x 0.40 = 9.6.

But - you can't have 9.6 of a student. So, we round up to 10.

Note that the question asks how many students <em>still need to complete</em> their assignment, meaning we are looking for the ones that haven't finished. We found the amount for students that <em>have</em> finished, so subtract that from the total to see approximately how many still have to finish.

24 - 10 = 14

So, this means approximately 14 students still need to complete their assignment.

I hope I could help you, have a great rest of your day! :D

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Step-by-step explanation:

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4 0
3 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
LB. Johnson middle school
Wewaii [24]

Answer:

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5 0
3 years ago
A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s
ANTONII [103]
<h2>Hello!</h2>

The answer is:

The ball will hit the ground after t=2.47s

<h2>Why?</h2>

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula.  We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

We are given the function:

h=-5t^{2}-3t+38

Where,

a=-5\\b=-3\\c=38

Then, substituting it into the quadratic equation, we have:

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s

Since negative time does not exists, the ball will hit the ground after:

t=2.473s=2.47s

Have a nice day!

4 0
3 years ago
Read 2 more answers
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