Answer:
i dk sorry
Step-by-step explanation:
Answer:
C) Distributive Property
Step-by-step explanation:
You're <em>distributing</em> in the 3 when you multiply it by the 5 and the 2 in the algebraic process:
➦ ➦
3•(5 + 2) = (3 • 5) + (3 • 2)
So, the 3 was <em>distributed</em> between the 5 and 2 when you multiplied.
Hence, this is the distributive property.
A function cannot be a function if any x is repeating. The x in A has the number 1 repeating. The x is C has 2 repeating the x in D has 1 repeating.
Therefore, our answer would be (B)
First list all the terms out.
e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...
Then, we can expand them.
e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...
Then, we can use the rules of raising i to a power.
e^ix = 1 + ix - x^2/2! - ix^3/3!...
Then, we can sort all the real and imaginary terms.
e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)
We can simplify this.
e^ix = cos x + i sin x
This is Euler's Formula.
What happens if we put in pi?
x = pi
e^i*pi = cos(pi) + i sin(pi)
cos(pi) = -1
i sin(pi) = 0
e^i*pi = -1 OR e^i*pi + 1 = 0
That is Euler's identity.
Answer:
is one
Step-by-step explanation:
its just one i know trust me
