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Setler [38]
3 years ago
11

What is 9.36•10~4 in standard form

Mathematics
1 answer:
marta [7]3 years ago
8 0
With exponents of 10, the exponent really just tells you how many zeroes there are behind the 1. So, for example, 10^4=10000 (4 zeroes behind 1). When multiplying decimals by exponents of 10, you move the decimal to the right, and the amount of places is the exponent number. For example, if I multiply 5.34 by 10^2, I move the decimal over to the right 2 times and get 534.

So, if you just multiply these you get 9.36*10000, which is 93600.
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Step-by-step explanation:

We are given the general quadratic formula, as " x = -b \frac{+}{-}  \sqrt{(b^2-4ac)} / 2a. " This can be represented by two separate formula's, which will come in handy when determining the positive and negative roots of the equation ( and here we need the negative root ):

1 ) x = - b+ ( \sqrt{b^2-4ac} ) / 2a,

2 ) x = - b- ( \sqrt{b^2-4ac} ) / 2a

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x = 5 + ( \sqrt{( - 5 )^2 - 4( 1 )( - 4 )} ) / 2( 1 ),\\x = 5 + ( \sqrt{25 + 16} ) / 2,\\x = 5 + \sqrt{41} / 2,\\x = ( About ) 5.7- This is our positive solution

__________

x = 5 - ( \sqrt{( - 5 )^2 - 4( 1 )( - 4 )} ) / 2( 1 ),\\x = 5 - ( \sqrt{25 + 16} ) / 2,\\x = 5 - \sqrt{41} / 2,\\x = ( About ) - 0.7- And this is our negative solution

You can see that - 0.7 is the negative real number solution to Joline's quadratic equation!

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