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2 years ago

The cosine of the complimentary angle to 58 degrees

Mathematics

1 answer:

lana [24]2 years ago

5 0

Yes
Divide it by sixty and multiply
I hope this helps

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Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.

Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

= 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$ .

Therefore, the area of the square is given by $\text{(side)}^2$

= $(r\sqrt 2)^2$

$= 2 r^2$

$= 2 (1)^2$

$=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

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2 years ago

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1 apple + 1 apple = 2 apples

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3 years ago

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(Z-6) divided by 3 for z= 15.9

scoray [572]

Simply plug in $\sf{z=15.9}$ into $\sf{\frac{z-6}{3}}$

So:

$\sf{\frac{15.9-6}{3}}$

Simplify that more:

$\sf{\frac{9.9}{3}}$

And that finally becomes

$\sf{3.3}$

So when $\sf{z=15.9}$ the answer will be $\boxed{\sf{3.3}}$

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2 years ago

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For a more see orthocenter of a triangle .The orthocenter is the point where all three altitude of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is a perpendicular to the opposite side. Hope this helps :)

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