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2 years ago

The cosine of the complimentary angle to 58 degrees

Mathematics

1 answer:

lana [24]2 years ago

5 0

Yes
Divide it by sixty and multiply
I hope this helps

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Find all values of $x$ such that $\sqrt{4x^2} - \sqrt{x^2} = 6$.

Eddi Din [679]

9514 1404 393

Answer:

x = -6 or 6

Step-by-step explanation:

The square root is always positive, so the equation simplifies to ...

$\sqrt{4x^2}-\sqrt{x^2}=6\\\\2|x|-|x|=6\\\\|x|=6\\\\x=\{-6,\ 6\}$

_____

The graph shows the solutions to f(x) = 0, where f(x) = √(4x²) -√(x²) -6.

4 0

2 years ago

Help me please *only answer*

Digiron [165]

Answer:

47 squre feet??

sorry if I'm wrong

5 0

2 years ago

1 4/5+ 2 2/3=what<br><br> 5 7/8 - 3 1/2=what<br> 1 1/2+ 3 1/5=what<br> 7 5/6- 5 1/2=what

lilavasa [31]

Answer:

1.) 4 7/15

2.) 2 3/8

3.) 4 7/10

4.) 2 1/3

Step-by-step explanation:

1.) 1 4/5 + 2 2/3

3 + 4/5 + 2/3

LCD = 15

3 + 12/15 + 10/15

3 + (12 + 10)/15

3 + 22/15

3 + 1 7/15

4 7/15

2.) 5 7/8 - 3 1/2

(5 x 8 + 7)/8 - 3 1/2

47/8 - 3 1/2

47/8 - (3 x 2 + 1)/2

47/8 - 7/2

LCD = 8

47/8 - 28/8

19/8

2 3/8

3.) 1 1/2 + 3 1/5

4 + 1/2 + 1/5

LCD = 10

4 + 5/10 + 2/10

4 + (5 + 2)/10

4 7/10

4.) 7 5/6 - 5 1/2

(7 x 6 + 5)/6 - 5 1/2

47/6 - 5 1/2

47/6 - (5 x 2 + 1)/2

47/6 - 11/2

LCD = 6

47/6 - 33/6

(47 - 33)/6

14/6

7/3

2 1/3

3 0

2 years ago

Read 2 more answers

Northridge Middle School collected 5022 cans of food for a food drive. Each of 18 homerooms collected the same number of cans. A

taurus [48]

Answer:

Step-by-step explanation:

Divide the total number of cans (5022) by the number of homerooms (18) to get the number of cans collected by each homeroom:

5022 cans

---------------------- = 279 cans per homeroom

18 homerooms

5 0

3 years ago

14. A company uses many different delivery

ziro4ka [17]

Answer:

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Sent by ABC Speedy Delivery Service.

Event B: Arrived on time.

The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.

This means that $P(A) = 0.71$

The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.

This means that $P(B|A) = 0.93$

Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)*P(A) = 0.93*0.71 = 0.6603$

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

8 0

2 years ago