The cosine of the complimentary angle to 58 degrees

Mathematics

1 answer:

lana [24]3 years ago

5 0

Yes
Divide it by sixty and multiply
I hope this helps

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Estimate using a rate per 100 of 74% of 315. 89% of 195

LiRa [457]

1. Given numbers:
74 % of 315
89% of 195

now, let’s solve the first given numbers:
=> 74% of 315
=> 315 is the 100%
Let’s convert 74% into decimals
=> 74% = .74
=> 315 * .74 = 233.1, the value of 74% of 315
Let’s solve the second given:
=> 89% of 195
where 195 is the 100%
=> 89% = .89
=> 195 * .89
=> 173.55, the value of 89% of 195

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Do these ratios form a proportion?

ad-work [718]

Answer:

Step-by-step explanation:

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Round 6709 to the nearest thousand

8090 [49]

7000 is 6709 rounded to the nearest thousand

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3 years ago

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Where does the normal line to the parabola y = x − x2 at the point (1, 0) intersect the parabola a second time?

Ksivusya [100]

Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)

we just need the slope

take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1

the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation

solve for where y=x-1 and y=x-x² intersect

set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero

x-1=0
x=1
we got this point already

x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2

it intersects at (-1,-2)

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3 years ago

98 Points !! These are follow up according to previous question that had been answered for me. Help would be appreciated ! :))

IgorLugansk [536]

That's a copy of the figure from the other post; I didn't look at the answer.

We have Start(0,0)

$A(-16.55\cos 25, -16.55 \sin 25)$

$B=A+(5 \cos 53, 5 \sin 53)$

$C=B+(20,0)$

$C=(-16.55\cos 25 + 5 \cos 53+20, -16.55 \sin25 - 5 \sin 53)$

$C \approx (8.00968, -10.9875) \approx(8,-11)$

Your team takes the direct path at a constant speed of 6 miles per hour.

Our team. $T=\sqrt{8^2+11^2}/6 = 2.27 \textrm{ hours}$

Team Red follows the riddle and travels at 8 mph from Start to Post A, 9 mph from Post A to Post B, and 11 mph from Post B to Finish.

$T=16.55/8 + 5/9 + 20/11 = 4.44 \textrm{ hours}$

Team Blue follows the riddle and travels at a constant speed of 10 mph.

 $T=(16.55 + 5 + 20)/10 = 4.155 \textrm{ hours}$

Team Yellow follows the riddle and travels at a constant speed of 11 mph, but stops at Post A for 30 minutes and stops again at Post B for another 30 minutes.

$T=(16.55 + 5 + 20)/11 + 30/60 + 30/60=4.78 \textrm{ hours}$

Winner: our team, then Blue, then Red, then Yellow

3 0

3 years ago