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2 years ago

6

a girl walks 4 km towards west, then she walks 3 km in a direction 30° east of north and stops. determine the girl’s displacemen

t from her initial point of departure.

1 answer:

kozerog [31]2 years ago

5 0

She on the north side

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3.57 x 10 <br> write in standard form

Bess [88]

$\huge\text{Hey there!}$

$\textsf{3.57}\times\textsf{10}^\mathsf{3}\\\\\mathsf{10^3}\\\mathsf{\rightarrow 10\times10\times10}\\\mathsf{\rightarrow100\times10}\\\mathsf{\rightarrow 1,000}\\\\\textsf{3.57}\times\textsf{1,000}\\\rightarrow\textsf{3,570}\\\rightarrow\mathsf{3.57\times10^3}\\\\\huge\boxed{Answer: {\frak{3.57\times 10^3}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

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2 years ago

Select a counter-example that makes the conclusion false.

Leya [2.2K]

The statement is False.

For this, it is enough to show a case in which the subtraction of two positive numbers is negative.

For this, we must choose two numbers.

Suppose we want to subtract the following numbers:

Number 1: 5

Number 2: 10

Subtracting both numbers we have:

$5 - 10 = -5$

We observe that the result is negative. Therefore, the given conclusion is false.

Answer:

Counterexample:

$5-10 = -5$

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2 years ago

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2 years ago

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saul85 [17]

Answer:

slope 1.5, passes through (0, 5) 62/87,21 Substitute m = 1.5 and ( x, y) = (0, 5) in the equation y

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2 years ago

Prove the identity secxcscx(tanx+cotx)=2+tan^2x+cot^2x

svetlana [45]

Hello,

$sec(x)= \dfrac{1}{cos(x)} \\

cosec(x)= \dfrac{1}{sin(x)} \\

sec(x)*cosec(x)*(tg(x)+cotg(x))=\dfrac{1}{cos(x)}* \dfrac{1}{sin(x)}*( \frac{sin(x)}{cos(x)} +\frac{cos(x)}{sin(x)})\\

= \dfrac{sin^2(x)+cos^2(x)}{sin^2x*cos^2x} \\

= \dfrac{1}{sin^2x*cos^2x} \\

$
==============================================================
$2+tg^2(x)+cotg^2(x)=2+ \dfrac{sin^2x}{cos^2x} + \dfrac{cos^2x}{sin^2x} \\

=2+ \dfrac{sin^4x+cos^4x}{sin^2x*cos^2x} \\

=\dfrac{2*sin^2x*cos^2x+sin^4x+cos^4x}{sin^2x*cos^2x} \\

= \dfrac{(sin^2x+cos^2x)^2}{sin^2x*cos^2x}} \\

= \dfrac{1}{sin^2x*cos^2x}} 
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2 years ago

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