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3 years ago

6

a girl walks 4 km towards west, then she walks 3 km in a direction 30° east of north and stops. determine the girl’s displacemen

t from her initial point of departure.

1 answer:

kozerog [31]3 years ago

5 0

She on the north side

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jolli1 [7]

Answer:

y=-50x+-10

Step-by-step explanation:

I'm assuming you need this answer in the y=mx+b format.

3 0

2 years ago

Question 5 (2) x cube - 3x square 9x - 5

kakasveta [241]

Please, post the instructions along with your question, and if possible share the question in symbolic form, not in words.

Do you mean Question #5? By (2) x cube, do you mean 2x^3?

I strongly suggest that you use lots of parentheses ( ) to show how your numbers are grouped, and not to use " x " to denote multiplication (use " * " for that, please.

If only you'll clear this up, I'd be happy to help.

I will assume that your post is 2x^3 - 3(9x-5)^2.

Then 2x^3 - 3(81x - 90x + 25). Does this have any resemblance to what you wanted me to see in your post?

3 0

3 years ago

Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?

Anit [1.1K]

Answer:

$\dfrac{p^{7} q}{160}$

Step-by-step explanation:

$\dfrac{(4p^-4 q)^-2}{10pq^-3} =$

$= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}$

$= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}$

$= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}$

$= \dfrac{1}{160}p^{7} q$

$= \dfrac{p^{7} q}{160}$

4 0

3 years ago

Read 2 more answers

How do I solve this ?

boyakko [2]

(1,-2) im pretty sure is the answer

8 0

3 years ago

Read 2 more answers

I need help ! <br> <img src="https://tex.z-dn.net/?f=3%5Csqrt%7B5%7D%20%2B5%5Csqrt%7B15%7D" id="TexFormula1" title="3\sqrt{5} +5

Feliz [49]

Answer:

26

Step-by-step explanation:

SORRY IF IM WRONG

6 0

2 years ago