Question

A jar contains 9 pennies, 10 nickels, 12 dimes, and 5 quarters. A coin is chosen, not replaced, then another is chosen. What is the probability of getting a nickel, then a dime? I need the answer in Fraction form. ​

Answer 1

Answer:

The probability of getting a nickel, then a dime is 2/21

Step-by-step explanation:

No. of pennies = 9

No. of nickels = 10

No. of dimes = 12

No. of quarters = 5

Total items = 9+10+12+5=36

So, Probability of getting nickel on first draw = $\frac{10}{36}$

Now the nickle in not replaced

So, Total items = 36-1 = 35

So, Probability of getting dime on second draw =$\frac{12}{35}$

So, the probability of getting a nickel, then a dime = $\frac{10}{36} \times \frac{12}{35}=\frac{2}{21}$

Hence the probability of getting a nickel, then a dime is 2/21