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Oxana [17]
3 years ago
11

Urgent please help!!

Mathematics
1 answer:
Inessa [10]3 years ago
5 0
The scale factor is 0.35. This is because that's what the sides of the larger figure has been multiplied by.
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Which set of ordered pairs represents y as a function of x?
il63 [147K]

Answer:

C.

Step-by-step explanation:

The set of ordered pairs can only be a function if the x value is not repeated .Thus,only C is a function as the x values (-1,4,1,-3) are unique while the other options have a repetition of its certain x values.

I hope ive helped

6 0
2 years ago
Is my answer correct?
Dmitry_Shevchenko [17]
Yes your answer is correct
8 0
2 years ago
C) A researcher has extracted two samples from the same target population, sample A and sample B. Sample A has a mean of 25 kg w
aleksandrvk [35]

Answer:

dsgberhyujxgkloyjnhbgfvbhnjklkjhbgfdfghjkiopolkjhgfew

Step-by-step explanation:

3 0
2 years ago
Solve please i’ll give brainliest
valina [46]

Answer:

3 is 60°, as well as 5 and 7 and the rest are 120°

Step-by-step explanation:

6 0
3 years ago
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
2 years ago
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