Answer: The required equation is and the number of fishes in the pond on June 1 = 115
Step-by-step explanation:
Given: The number of fishes in pond on July 1 = 63
Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.
Let f be the number of fishes in pounds on June 1.
then the required equation will be
Now, add 52 on both the sides of the equation, we get
Answer:
H 0 : μ = 3.1 H 1 : μ > 3.1
And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.
The p value is:
The significance level is: 0.1 or 10%
And since the p value is very low compared to the significance level we have enough evidence to:
Reject the null hypothesis
Step-by-step explanation:
For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:
H 0 : μ = 3.1 H 1 : μ > 3.1
And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.
We have the following info given:
The statistic to check the hypothesis is given by:
Replacing the info given we got:
The degrees of freedom are given by:
The p value since is a right tailed ted is given by:
The significance level is 0.1 or 10%
And since the p value is very low compared to the significance level we have enough evidence to:
Reject the null hypothesis