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dimulka [17.4K]

3 years ago

12

Veronika’s five test scores are 59, 80, 95, 88, and 93. If the outlier of 59 is removed, what is the mean absolute deviation of

the remaining four test scores?
A.4.5
B.5
C.10.8
D.36

2 answers:

frosja888 [35]3 years ago

7 0

The answer is B.5 hope this helps

jarptica [38.1K]3 years ago

6 0

Answer:

B. 5

Step-by-step explanation:

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Please help. I don't understand.

love history [14]

Answer: D

Step-by-step explanation:

The construction of a triangle tangent to the three sides would require the construction of the incircle.

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3 years ago

Construct a triangle abc with ab=7cm angle a=angle b= 55 .what kind of angle is this.

Vedmedyk [2.9K]

Step-by-step explanation:

I think this would be an Isosceles triangle

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3 years ago

You are working as an apprentice for the bksb Newcastle Arena. The arena is hosting a photography show. The exhibition space is

elena55 [62]

Answer:

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Step-by-step explanation:

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3 years ago

(1 point) A, P and D are n×n matrices. Check the true statements below: A. A is diagonalizable if and only if A has n eigenvalue

yarga [219]

Answer:

Following are the answers to this questions:

A) False.

B) False.

C) True.

D) True.

Step-by-step explanation:

In option A,

Let A is $3 \times 3$ diagonal matrices that is,

$\left[\begin{array}{ccc}0&1&0\\0&0&6\\0&0&0\end{array}\right]$

here $A^3$ = 0, In this A is the nilpotent matrix and A has three values that are equal to 0 but it is not a diagonalizable matrix.

In option B,

If $A =\left[\begin{array}{ccc}0&1\\0&0\end{array}\right]$ in given value A elements are 0 and 1 as a distinct eigen value, that's why A is diagonalizable but |A| =0 its means A is not invertible, that's why it is false.

In option C,

It is given that $A= PDP^{-1}$ where A~ D, which is A is similar to diagonal matrices, that's why it is true.

In option D,

It is given that A has eigen vector, which leases from $R^n$ . A has eigen vector and A is $n \times n$ matrix, the number of A eigen values = given vector of A, that's why it is correct.

8 0

3 years ago

Express sin A,cos A and tan A as ratios

OverLord2011 [107]

Answer:

Part A) $sin(A)=\frac{2\sqrt{42}}{23}$

Part B) $cos(A)=\frac{19}{23}$

Part C) $tan(A)=\frac{2\sqrt{42}}{19}$

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

so

$sin(A)=\frac{BC}{AB}$

substitute the values

$sin(A)=\frac{2\sqrt{42}}{23}$

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

so

$cos(A)=\frac{AC}{AB}$

substitute the values

$cos(A)=\frac{19}{23}$

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

so

$tan(A)=\frac{BC}{AC}$

substitute the values

$tan(A)=\frac{2\sqrt{42}}{19}$

8 0

3 years ago