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dimulka [17.4K]
3 years ago
12

Veronika’s five test scores are 59, 80, 95, 88, and 93. If the outlier of 59 is removed, what is the mean absolute deviation of

the remaining four test scores?
A.4.5
B.5
C.10.8
D.36
Mathematics
2 answers:
frosja888 [35]3 years ago
7 0
The answer is B.5 hope this helps

jarptica [38.1K]3 years ago
6 0

Answer:

B. 5

Step-by-step explanation:

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The margin of error of the random selection is 0.29

The given parameters are:

n = 320 --- the sample size

\sigma = 2.9 --- the standard deviation

\bar x = 24 --- the mean

\alpha = 90\% --- the confidence level.

The margin of error (E) is calculated as follows:

E = z \times \sqrt{\frac{\sigma^2}{n}}

So, we have:

E = z \times \sqrt{\frac{3.2^2}{320}}

E = z \times \sqrt{\frac{10.24}{320}}

The z-value for 90% confidence level is 1.645.

Substitute 1.645 for z

E = 1.645 \times \sqrt{\frac{10.24}{320}}

E = 1.645 \times \sqrt{0.032}

Take square roots

E = 1.645 \times 0.1789

Multiply

E = 0.2943

Approximate

E = 0.29

Hence, the margin of error is 0.29

Read more about margin of error at:

brainly.com/question/14396648

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Answer:

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Step-by-step explanation:

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Round the result to the hundredths place.

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