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ahrayia [7]
3 years ago
7

The​ _______ of a discrete random variable represents the mean value of the outcomes.

Mathematics
2 answers:
USPshnik [31]3 years ago
3 0

Answer:

expected value

Step-by-step explanation:

artcher [175]3 years ago
3 0

Answer:

Expected value

Step-by-step explanation:

Expected value- Any discrete variable's expected value is probability-weighted average of all of its possible values.

In simple words, any possible value that can be inferred by the any given variable is compounded by its probability of occurrence and the resulting products are added up to deliver the expected value.

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From the equation y=3.5x identify the constant of proportionality
Ilya [14]

Answer:

3.5

Step-by-step explanation:

5 0
2 years ago
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1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
1 of 6
nasty-shy [4]

Answer:

something

Step-by-step explanation:

sry i need answers

3 0
2 years ago
The square root of a number is between 10 and 11. Which of these could be that number?
kaheart [24]
The answer would be 105, it's square root is approximately 10.2469 <span />
7 0
3 years ago
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Will mark BRAINLIEST!!!
svlad2 [7]

Answer:

answer choice c is correct

:)

hope that helped. <3

<em>bye now! </em>

<em>have a nice day too <3.</em><u><em> k bye</em></u>

7 0
3 years ago
Read 2 more answers
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