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kiruha [24]
3 years ago
6

The floor area of a square room is 225 sq. ft. What is the measure of each side of the room in feet?

Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

56.25 feet

Step-by-step explanation:

225 divided by 4 is 65.25

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Determine f(-1) if the graph of f(x) is given below.
-BARSIC- [3]

Answer:

f(-1) = -2

Step-by-step explanation:

Given

The attached graph

Required

f(-1)

This is the point where

x = -1

On the attached graph;

f(x) = -2 when x = -1

Hence:

f(-1) = -2

8 0
3 years ago
Which expression is equivalent to 6/7 divided by 3/5 ?
Harman [31]

Answer:

A.

Step-by-step explanation:

6/7  / 3/5   we invert the divisor and multiply:

= 6/7 * 5/3

8 0
3 years ago
I need this answered asap i will mark brainliest.
Harlamova29_29 [7]

I typed right on the problem set.

4 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
What is the slope of the line through (3,2) and (-3,4)?
NISA [10]

Answer:

slope = - \frac{1}{3}

Step-by-step explanation:

calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (3, 2 ) and (x₂, y₂ ) = (- 3, 4 )

m = \frac{4-2}{-3-3} = \frac{2}{-6} = - \frac{1}{3}

3 0
2 years ago
Read 2 more answers
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