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2 years ago

Find two fractions that are between 3/5 & 4/5

Mathematics

2 answers:

vivado [14]2 years ago

7 0

3/5=6/10=60/100 and 4/5=8/10=80/100 So, two fractions between 3/5 and 4/5 would be 65/100 and 75/100

Ahat [919]2 years ago

3 0

$\frac{3}{5} = \frac{3\times 2}{5\times 2} = \frac{6}{10} \\\\ \frac{4}{5} = \frac{4\times 2}{5\times 2} = \frac{8}{10}$

A few fractions in between 3/5 and 4/5 is 7/10, 13/20, and 15/20.

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3 years ago

Log16^*+log4^*+log2^*=7

ale4655 [162]

Answer:

$x = 16$

Step-by-step explanation:

Given

$log_{16}(x) + log_4(x) + log_2(x) = 7$

Required

Solve for x

$log_{16}(x) + log_4(x) + log_2(x) = 7$

Change base of 16 and base of 4 to base 2

$\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7$

Express 16 and 4 as 2^4 and 2^2 respectively

$\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7$

The above can be rewritten as:

$\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7$

$log_22 = 1$

So, we have:

$\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7$

$\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7$

Multiply through by 4

$4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4$

$log_2(x) + 2}log_2(x) + 4log_2(x) = 28$

$7log_2(x) = 28$

Divide through by 7

$\frac{7log_2(x)}{7} = \frac{28}{7}$

$log_2(x) = 4$

Apply the following law of logarithm:

If $log_ab = c$ Then $b = a^c$

So, we have:

$x = 2^4$

$x = 16$

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3 years ago

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Answer:

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8 0

2 years ago