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maw [93]
2 years ago
14

Find two fractions that are between 3/5 & 4/5

Mathematics
2 answers:
vivado [14]2 years ago
7 0
3/5=6/10=60/100 and 4/5=8/10=80/100 So, two fractions between 3/5 and 4/5 would be 65/100 and 75/100
Ahat [919]2 years ago
3 0
\frac{3}{5} = \frac{3\times 2}{5\times 2} = \frac{6}{10} \\\\ \frac{4}{5} = \frac{4\times 2}{5\times 2} = \frac{8}{10}

A few fractions in between 3/5 and 4/5 is 7/10, 13/20, and 15/20.
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Log16^*+log4^*+log2^*=7​
ale4655 [162]

Answer:

x = 16

Step-by-step explanation:

Given

log_{16}(x) + log_4(x) + log_2(x) = 7

Required

Solve for x

log_{16}(x) + log_4(x) + log_2(x) = 7

Change base of 16 and base of 4 to base 2

\frac{log_2(x)}{log_2(16)} + \frac{log_2(x)}{log_2(4)} + log_2(x) = 7

Express 16 and 4 as 2^4 and 2^2 respectively

\frac{log_2(x)}{log_2(2^4)} + \frac{log_2(x)}{log_2(2^2)} + log_2(x) = 7

The above can be rewritten as:

\frac{log_2(x)}{4log_22} + \frac{log_2(x)}{2log_22} + log_2(x) = 7

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So, we have:

\frac{log_2(x)}{4*1} + \frac{log_2(x)}{2*1} + log_2(x) = 7

\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x) = 7

Multiply through by 4

4(\frac{1}{4}log_2(x) + \frac{1}{2}log_2(x) + log_2(x)) = 7 * 4

log_2(x) + 2}log_2(x) + 4log_2(x) = 28

7log_2(x) = 28

Divide through by 7

\frac{7log_2(x)}{7} = \frac{28}{7}

log_2(x) = 4

Apply the following law of logarithm:

<em>If </em>log_ab = c<em> </em><em>Then </em>b = a^c<em></em>

So, we have:

x = 2^4

x = 16

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Answer:

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