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skelet666 [1.2K]
3 years ago
9

3b 2a=5a−6 solve the equation for a in terms of b.

Mathematics
1 answer:
oee [108]3 years ago
4 0
Is it 3b-2a=5a-6
or
3b+2a=5a-6

you are missing the sign of 2a
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7.89 greater or less than 7.189<br><br> 6.030 greater less or equal 6.03
NemiM [27]
7.89 is greater than 7.189,  6.03 is equal to 6.030, because that last zero doesn't really change anything it cancels itself out
5 0
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How do I solve 8 - 4x + 5y when x = -2 and y = 6
Oliga [24]
8 - 4(-2) + 5(6)
8 + 8 + 30
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3 years ago
If (3-4i) (x+iy) = 3 root 5<br> show that x^2 + y^2=9/5
NNADVOKAT [17]

Answer:

the answer is 2 + i.

Step-by-step explanation:

Let the square root of 3 + 4i be x + iy.

So (x + iy) (x +iy) = 3 +4i

=> x^2 + xyi + xyi + i^2*y^2 = 3 + 4i

=> x^2 – y^2 + 2xyi = 3 + 4i

Equate the real and complex terms

=> x^2 - y^2 = 3 and 2xy = 4

2xy = 4

=> xy = 2

=> x = 2/y

Substitute in

=> x^2 - y^2 = 3

=> 4/y^2 - y^2 = 3

=> 4 – y^4 = 3y^2

=> y^4 + 3y^2 – 4 = 0

=> y^4 + 4y^2 – y^2 – 4 =0

=> y^2(y^2 + 4) – 1(y^2 + 4) =0

=> (y^2 – 1) (y^2 + 4) =0

Therefore y^2 = 1, we ignore y^2 = -4 as it gives complex values of y.

Therefore y = 1 and x = 2/1 = 2

The required square root of 3 + 4i is 2 + i.

5 0
3 years ago
8Answers and questions attached* please tell me the correct answer
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Answer:

I do not know

Step-by-step explanation:

because 150 spins is way too much

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3 years ago
Given triangle DOG is congruent to triangle CAT, which reason could you use to prove that angle G is congruent to angle T?​
quester [9]

Answer:

The correct option is;

d) CPCTC

Step-by-step explanation:

The phrase Corresponding Parts of Congruent Triangles are Congruent with the acronym CPCTC, is used as valid reasoning in the provision of a proof, after the existence of congruency between two triangles has been proven

Given that the triangles ΔDOG and ΔCAT have been proven congruent, we have that the corresponding vertices are;

Vertex D corresponds to vertex C

Vertex O corresponds to vertex A

Vertex G corresponds to vertex T

Therefore, given that ΔDOG ≅ ΔCAT, we have;

∠D ≅ ∠C by CPCTC

∠O ≅ ∠A by CPCTC

∠G ≅ ∠T by CPCTC.

3 0
2 years ago
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