3 years ago

How do I solve 8 - 4x + 5y when x = -2 and y = 6

Mathematics

1 answer:

Oliga [24]3 years ago

3 0

8 - 4(-2) + 5(6)
8 + 8 + 30
=46

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Please solve this<br><img src="https://tex.z-dn.net/?f=%20%7Cx%20%5E%7B2%7D%20%2B%203x%20-%201%20%7C%20%20%3C%203" id="TexFormul

klasskru [66]

$\bf |x^2+3x-1|\ \textless \ 3\implies 
\begin{cases}
+(x^2+3x-1)\ \textless \ 3\\\\
-(x^2+3x-1)\ \textless \ 3
\end{cases}\\\\
-------------------------------\\\\
x^2+3x-1\ \textless \ 3\implies x^2+3x-4\ \textless \ 0\implies (x+4)(x-1)\ \textless \ 0
\\\\\\
x\ \textless \ 
\begin{cases}
-4\\
1
\end{cases}\\\\
-------------------------------\\\\
-(x^2+3x-1)\ \textless \ 3\implies x^2+3x-1\boxed{\ \textgreater \ }-3
\\\\\\
x^2+3+2\ \textgreater \ 0\implies (x+2)(x+1)\ \textgreater \ 0\implies x\ \textgreater \ 
\begin{cases}
-2\\
-1
\end{cases}$