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weqwewe [10]
3 years ago
14

How do I solve 8 - 4x + 5y when x = -2 and y = 6

Mathematics
1 answer:
Oliga [24]3 years ago
3 0
8 - 4(-2) + 5(6)
8 + 8 + 30
=46
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Answer:

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Step-by-step explanation:

−1/2 − (−4/5) = x

First, switch sides.

x = −1/2 − (−4/5)

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2 years ago
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Alona [7]

Answer:

\large\boxed{1.\ (4)^{-3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}}

\large\boxed{2.\ ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x}

Step-by-step explanation:

Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\\------------\\\\(4)^{-3x^2}=\left[(4)^{-1}\right]^{3x^2}=\left(\dfrac{1}{4}\right)^{3x^2}

Use:\ a^{-n}=\left(\dfrac{1}{a}\right)^n\ and\ (a^n)^m=a^{nm}\\--------------------\\\\ab^{-3x}=a\cdot b^{-3x}=a\left[(b)^{-1}\right]^{3x}=a\left(\dfrac{1}{b}\right)^{3x}\\\\ab^{-3x}=a\left(\dfrac{1}{b}\right)^{3x}=a\left[\left(\dfrac{1}{b}\right)^3\right]^x

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3 years ago
Which function is defined for x=0
Sav [38]

0 would be on the top, hope this helps

4 0
3 years ago
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