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Alenkinab [10]
3 years ago
15

Team A and Team B play in a competition.

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
8 0
Team A: 15 points
Team B: 3 points

Team A has twelve more points than Team B:
A = B + 12
Team A has five times as many points as Team B:
A = B × 5
A = 5B

substitute "A" with "B + 12" to solve for B:
A = 5B
(B + 12) = 5B
B + 12 = 5B
12 = 5B - B
12 = 4B
3 = B
Team B has 3 points
now substitute "B" with 3 to solve for A:
A = 5B
A = 5(3)
A = 15
Team A has 15 points

Check your answer by inputting both values into either equation:
A = 5B
(15) = 5(3)
15 = 15 ✔

A = B + 12
(15) = (3) + 12
15 = 15 ✔
Ierofanga [76]3 years ago
8 0
Let's say team B has x points. That means that team A has x+12 points, or 5x points, as mentioned in the question. If the points that Team A has acquired can both be represented as x+12 and 5x, then these values are equal and solved for 'x':
x+12=5x
Minus x on both sides
12=4x
Divide both sides by 4
3=x
So, Team B (x) has 3 points, and Team A (x+12 or 5x) has 15 points.
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<em>y = mx + b</em>

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Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e.  135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

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since  135.8< 137 < 155.9

So , it is usual.

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So , it is unusual.

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since  135.8< 146 < 155.9

So , it is usual.

d. 155  

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

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